我有一个用 python 编写的 lambda 函数，它在 mongodb 中执行一些操作，然后它应该将函数的 tmp 文件夹中的图片上传到 s3 上。该函数在上传步骤中不断超时。
我将超时设置为 2 分钟，并且该函数具有 S3 和 vpc 权限。该函数只是超时。任何人都知道出了什么问题吗？
输入样本
#picturename should be created by the app. a name unique for the dish
{
"UserId": "56dc63fc1769d032d4d78e2e",
"DishId": "56dcc2781769d032d4d78e2f",
"PictureName" : "katsu-001.png",
"Data": "base64 image just the bits ignore data:image/jpeg;base64, if you have it"
}
Function
def addPicture(event,context):
from __future__ import print_function
import pymongo
from pymongo import MongoClient
import bson.code
from bson.objectid import ObjectId
import datetime
import json
import boto3
import sys
import uuid
from base64 import decodestring
print ('Writing file to disk')
with open('/tmp/' + pictureName,"wb") as f:
f.write(decodestring(event["Data"]))
print ('File written to /tmp/' + pictureName)
s3_client = boto3.client('s3')
print ('Starting S3 upload')
bucket = "foundue-dev-filestore"
upload_path = 'pictures/dish/' + dishId.__str__() + '/' + pictureName
print ('Uploading /tmp/' + pictureName + ' ' + bucket + ' ' + upload_path)
s3_client.upload_file('/tmp/' + pictureName,bucket, upload_path)
print ('Upload Complete')
#pics[pictureName] = upload_path
#dish["Pictures"] = pics
#dish["UpdatedOn"] = datetime.datetime.utcnow()
#db.dishes.replace_one({"_id": dishId}, dish)
return
lambda 附加策略
oneClick_lambda_basic_vpc_execution_1457284829450
oneClick_lambda_s3_exec_role_1457392283800
Output
Loading function
START RequestId: ed91c290-e582-11e5-95d6-ed4fc6a3321b Version: $LATEST
Writing file to disk
File written to /tmp/katsu-002png
Starting S3 upload
Uploading /tmp/katsu-002png foundue-dev-filestore pictures/dish/56dcc2781769d032d4d78e2f/katsu-002png
END RequestId: ed91c290-e582-11e5-95d6-ed4fc6a3321b
REPORT RequestId: ed91c290-e582-11e5-95d6-ed4fc6a3321b Duration: 121003.49 ms Billed Duration: 121000 ms Memory Size: 128 MB Max Memory Used: 22 MB
2016-03-08T23:12:21.437Z ed91c290-e582-11e5-95d6-ed4fc6a3321b Task timed out after 121.00 seconds
