R 如何在另一个函数中将函数作为字符串传递

对于这个小难题的任何帮助将不胜感激。

我正在尝试向tq_transmute函数从tidyquant包裹;参数的值是一个函数，但是我想将其作为字符串传递（在下面示例的范围内，我将通过 Shiny 传递它）selectInput).

我已经尝试了所有我能想到的方法将字符串“apply.quarterly”转换为对象apply.quarterly接受的mutate_fun争论。注释行是我失败的尝试。

最终，我想将这个概念扩展到其他论点，即FUN = max to FUN = ‘max’.

library(tidyverse)
library(tidyquant)
library(rlang)

FANG %>%
  group_by(symbol) %>%
  tq_transmute(select     = adjusted, 
               mutate_fun = apply.quarterly,
               # mutate_fun = sym('apply.quarterly'),
               # mutate_fun = syms('apply.quarterly'),
               # mutate_fun = !!sym('apply.quarterly'),
               # mutate_fun = !!!sym('apply.quarterly'),
               # mutate_fun = eval(parse('apply.quarterly')),
               # mutate_fun = eval(substitute('apply.quarterly')),
               # mutate_fun = enquo('apply.quarterly'),
               # mutate_fun = expr(!!enquo('apply.quarterly')),
               # mutate_fun = quo('apply.quarterly'),
               # mutate_fun = enquos('apply.quarterly'),
               # mutate_fun = enquote('apply.quarterly'),
               # mutate_fun = quote('apply.quarterly'),
               # mutate_fun = substitute('apply.quarterly'),
               # mutate_fun = parse('apply.quarterly'),
               # mutate_fun = parse('apply.quarterly'),
               # mutate_fun = ensym('apply.quarterly'),
               # mutate_fun = rlang::as_function('apply.quarterly'),
               # mutate_fun = rlang::as_closure('apply.quarterly'),
               # mutate_fun = rlang::as_quosure('apply.quarterly'),
               # mutate_fun = rlang::as_quosure('apply.quarterly'),
               # mutate_fun = enexpr('apply.quarterly'),
               # mutate_fun = enexprs('apply.quarterly'),
               # mutate_fun = ensym('apply.quarterly'),
               # mutate_fun = ensyms('apply.quarterly'),
               # mutate_fun = eval_tidy('apply.quarterly'),
               # mutate_fun = exprs('apply.quarterly'),
               # mutate_fun = expr_deparse('apply.quarterly'),
               # mutate_fun = expr_label('apply.quarterly'),
               # mutate_fun = expr_label(substitute('apply.quarterly')),
               # mutate_fun = expr_label(quote('apply.quarterly')),
               # mutate_fun = parse_expr('apply.quarterly'),
               # mutate_fun = quasiquotation('apply.quarterly'),
               # mutate_fun = quotation('apply.quarterly'),
               # mutate_fun = quotation('apply.quarterly'),
               FUN        = max, 
               col_rename = "max.close")

您可以使用blast()用于立即评估的准报价

blast <- function(expr, env = caller_env()) {
  eval_bare(enexpr(expr), env)
}

blast(list(!!!1:3))
#> [[1]]
#> [1] 1
#>
#> [[2]]
#> [1] 2
#>
#> [[3]]
#> [1] 3

Then

myfun <- "apply.quarterly"

blast(
  FANG %>%
    group_by(symbol) %>%
    tq_transmute(
      select = adjusted,
      mutate_fun = !!sym(myfun),
      FUN = max,
      col_rename = "max.close"
    )
)