使用 Objective-C/Cocoa 启动 Mac 应用程序

使用命令行启动路径查找器应用程序时，我使用open -a Path Finder.app /Users/。 基于这个想法，我使用以下代码来启动路径查找器。

我可以在不使用的情况下启动应用程序吗open命令行？

NSTask *task;
task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/open"];

NSArray *arguments;
arguments = [NSArray arrayWithObjects: @"-a", @"Path Finder.app", @"/Users/", nil];
[task setArguments: arguments];

NSPipe *pipe;
pipe = [NSPipe pipe];
[task setStandardOutput: pipe];

NSFileHandle *file;
file = [pipe fileHandleForReading];

[task launch];

if(![[NSWorkspace sharedWorkspace] launchApplication:@"Path Finder"])
    NSLog(@"Path Finder failed to launch");

带参数：

NSWorkspace *workspace = [NSWorkspace sharedWorkspace];
NSURL *url = [NSURL fileURLWithPath:[workspace fullPathForApplication:@"Path Finder"]];
//Handle url==nil
NSError *error = nil;
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[workspace launchApplicationAtURL:url options:0 configuration:[NSDictionary dictionaryWithObject:arguments forKey:NSWorkspaceLaunchConfigurationArguments] error:&error];
//Handle error

您还可以使用 NSTask 来传递参数：

NSTask *task = [[NSTask alloc] init];
NSBundle *bundle = [NSBundle bundleWithPath:[[NSWorkspace sharedWorkspace] fullPathForApplication:@"Path Finder"]]];
[task setLaunchPath:[bundle executablePath]];
NSArray *arguments = [NSArray arrayWithObjects:@"Argument1", @"Argument2", nil];
[task setArguments:arguments];
[task launch];