Java Scanner 类读取字符串

我得到以下代码：

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
names = new String[nnames];

for (int i = 0; i < names.length; i++){
  System.out.print("Type a name: ");
  names[i] = in.nextLine();
}

该代码的输出如下：

How many names are you going to save:3 
Type a name: Type a name: John Doe
Type a name: John Lennon

请注意它是如何跳过名字条目的？它跳过了它，直接进入第二个名字条目。我已经尝试寻找导致此问题的原因，但我似乎无法解决它。我希望有一个人可以帮助我。谢谢

错误的原因是nextInt只拉取整数，而不是换行符。如果您在 for 循环之前添加 in.nextLine() ，它将吃掉空的新行并允许您输入 3 个名称。

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();

names = new String[nnames];
in.nextLine();
for (int i = 0; i < names.length; i++){
        System.out.print("Type a name: ");
        names[i] = in.nextLine();
}

或者只是读取该行并将该值解析为整数。

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = Integer.parseInt(in.nextLine().trim());

names = new String[nnames];
for (int i = 0; i < names.length; i++){
        System.out.print("Type a name: ");
        names[i] = in.nextLine();
}