我需要解析包含一长串客户列表的 JSON 文件。在 JSON 文件中,每个客户可能有一个 id 作为字符串:
{
"cust_id": "87655",
...
},
或者一些 id 作为数组:
{
"cust_id": [
"12345",
"45678"
],
...
},
The Customer
类如下:
public class Customer {
@SerializedName("cust_id")
@Expose
private String custId;
public String getCustId() {
return custId;
}
public void setCustId(String custId) {
this.custId = custId;
}
}
我使用 Gson 解析 JSON:
Gson gson = new Gson()
Customers customers1 = gson.fromJson(json, Customers.class)
它失败了com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected a string but was BEGIN_ARRAY
当它尝试解析数组时。
失败的原因很清楚。
我的问题:处理这两种情况的最佳方法是什么(当 id 是一个字符串时,当它是一个字符串数组时),给定我无法更改 json 文件结构?
如果您想处理这两种情况,您可以使用自定义解串器。当然,您必须将“cust_id”变量更改为列表或数组。
Main:
String json1 = "{\"cust_id\": \"87655\"}";
String json2 = "{\"cust_id\": [\"12345\", \"45678\"]}";
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(Customer.class, new CustomerDeserializer());
Gson gson = gsonBuilder.create();
Customer customer1 = gson.fromJson(json1, Customer.class);
System.out.println(customer1);
Customer customer2 = gson.fromJson(json2, Customer.class);
System.out.println(customer2);
Customer
public class Customer {
@SerializedName("cust_id")
private List<String> custId;
public List<String> getCustId() {
return custId;
}
public void setCustId(List<String> custId) {
this.custId = custId;
}
}
客户解串器
public class CustomerDeserializer implements JsonDeserializer<Customer> {
@Override
public Customer deserialize(JsonElement jsonElement, Type typeOf, JsonDeserializationContext context) throws JsonParseException {
Customer result = null;
Gson gson = new Gson();
try {
// try to deserialize by assuming JSON has a list
result = gson.fromJson(jsonElement, Customer.class);
} catch (JsonSyntaxException jse) {
// error here means JSON has a single string instead of a list
try {
// get the single ID
String custId = jsonElement.getAsJsonObject().get("cust_id").getAsString();
result = new Customer();
result.setCustId(Arrays.asList(new String[] {custId}));
} catch (Exception e) {
// more error handling here
e.printStackTrace();
}
}
return result;
}
}
Output
Customer [custId=[87655]]
Customer [custId=[12345, 45678]]
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