在 SwiftUI 中动态获取视图的 Shape

使用 Swift 5.2 我想创建一个函数来动态更改Shape

我有一个像

import SwiftUI

struct CardView: View {
    let suit : Suite
    let rank : Rank
    var body: some View {
        getShape(suite: .heart)
        .fill(Color.red)  // .fill(suit.color)
        .frame(width: 100, height: 100)
     }
}

我想创建一个协议返回类型为 Shape 的函数，我在下面的示例中用自定义形状替换了通用形状

func getShape(suite:Suite) -> Shape {
    switch suite {
    case .heart:
        return Circle() // Heart()
    case .diamond:
        return Rectangle() // Diamond()
    case .spade:
        return Circle() // Heart()
    case .club:
        return Circle() // Club()

    }
}

我不能使用不透明类型some因为我返回不同的类型并且收到编译错误

Function declares an opaque return type, but the return statements in its body do not have matching underlying types 

我也不能将其保留为协议类型，因为我收到错误

Protocol 'Shape' can only be used as a generic constraint because it has Self or associated type requirements

有什么办法可以优雅地实现这一点吗？

通过将@Asperi的答案与

struct AnyShape: Shape {
    init<S: Shape>(_ wrapped: S) {
        _path = { rect in
            let path = wrapped.path(in: rect)
            return path
        }
    }

    func path(in rect: CGRect) -> Path {
        return _path(rect)
    }

    private let _path: (CGRect) -> Path
}

我可以将其更改为

func getShape(suite:Suite) -> some Shape {
    switch suite {
    case .club:
        return AnyShape(Club())
    case .diamond:
        return AnyShape(Diamond())
    case .heart:
        return AnyShape(Heart())

    case .spade:
        return AnyShape(Spade())
    }
}


struct CardView: View {
    let suit : Suite
    let rank : Rank
    var body: some View {

    getShape(suite: suit)
      .fill(Color.red)
      .frame(width: 100, height: 100)
 }