我有以下内容OrderedDict:
from collections import OrderedDict
a = OrderedDict()
a['2016:April'] = 1
a['2016:January'] = 2
a['2017:February'] = 3
a['2015:November'] = 4
我想按时间顺序按键对字典进行排序，结果是：
OrderedDict([('2015:November', 4), ('2016:January', 2), ('2016:April', 1), ('2017:February', 3)])
您需要重新创建OrderedDict通过传递已排序的项目； （OrderedDict 记住键插入顺序）
import calendar
from collections import OrderedDict
months = {calendar.month_name[i]: i for i in range(1, 13)}
# => {'January': 1, 'February': 2, .... 'December': 12}
def get_month_from_key(item):
# Convert '2015:November' to (2015, 11)
# Return value of this function is used to compare dictionary keys.
year, month = item[0].split(':') # item[0] is key
return int(year), months.get(month, -1)
a = OrderedDict()
a['2016:April'] = 1
a['2016:January'] = 2
a['2017:February'] = 3
a['2015:November'] = 4
a = OrderedDict(sorted(a.items(), key=get_month_from_key))
# => OrderedDict([('2015:November', 4), ('2016:January', 2),
# ('2016:April', 1), ('2017:February', 3)])
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