我想让当前的网络接口处于活动状态并连接到互联网。
实际上,我可以检查网络是否正常以及是否不是环回网络。
foreach(QNetworkInterface interface, QNetworkInterface::allInterfaces())
{
if (interface.flags().testFlag(QNetworkInterface::IsUp) && !interface.flags().testFlag(QNetworkInterface::IsLoopBack))
foreach (QNetworkAddressEntry entry, interface.addressEntries())
{
if ( interface.hardwareAddress() != "00:00:00:00:00:00" && entry.ip().toString().contains("."))
items << interface.name() + " "+ entry.ip().toString() +" " + interface.hardwareAddress();
}
Results:
"en1 3.3.3.52 D4:9A:20:61:1F:72"
"vmnet1 192.168.169.1 00:50:56:C0:00:01"
"vmnet8 192.168.210.1 00:50:56:C0:00:08"
事实上它可以工作,但我还发现了虚拟机接口。
我只想选择 WLAN 接口和以太网接口。
很抱歉重提一个老问题,但我自己只是在思考这个问题并提出了一个解决方案:
QList<QString> possibleMatches;
QList<QNetworkInterface> ifaces = QNetworkInterface::allInterfaces();
if ( !ifaces.isEmpty() )
{
for(int i=0; i < ifaces.size(); i++)
{
unsigned int flags = ifaces[i].flags();
bool isLoopback = (bool)(flags & QNetworkInterface::IsLoopBack);
bool isP2P = (bool)(flags & QNetworkInterface::IsPointToPoint);
bool isRunning = (bool)(flags & QNetworkInterface::IsRunning);
// If this interface isn't running, we don't care about it
if ( !isRunning ) continue;
// We only want valid interfaces that aren't loopback/virtual and not point to point
if ( !ifaces[i].isValid() || isLoopback || isP2P ) continue;
QList<QHostAddress> addresses = ifaces[i].allAddresses();
for(int a=0; a < addresses.size(); a++)
{
// Ignore local host
if ( addresses[a] == QHostAddress::LocalHost ) continue;
// Ignore non-ipv4 addresses
if ( !addresses[a].toIPv4Address() ) continue;
QString ip = addresses[a].toString();
if ( ip.isEmpty() ) continue;
bool foundMatch = false;
for (int j=0; j < possibleMatches.size(); j++) if ( ip == possibleMatches[j] ) { foundMatch = true; break; }
if ( !foundMatch ) { possibleMatches.push_back( ip ); qDebug() << "possible address: " << ifaces[i].humanReadableName() << "->" << ip; }
}
}
}
// Now you can peek through the entries in possibleMatches
// With VMWare installed, I get two entries, and the first one is the correct one.
// If you wanted to test which one has internet connectivity, try creating a tcp
// connection to a known internet service (e.g. google.com) and if the connection
// is successful, check the following on the tcp connection
/*
if ( socket->localAddress().toIPv4Address() )
{
for(int c=0; c < possibleMatches.size(); c++) if ( socket->localAddress().toString() == possibleMatches[c] ) { qDebug() << "Your LAN IP:" << possibleMatches[c]; }
}
*/
你可能想让它更健壮一点,这样代码就可以跟踪接口和IP地址,但这可能是不必要的,因为我很确定一个接口不能容纳多个IP地址,并且没有两个接口可以具有相同的 IP 地址(如果我的假设错误,请纠正我)。
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