我正在为 iPhone 开发一个 Objective-C 应用程序。我的问题是我的应用程序必须保存从网址获取的图像。我认为该文件夹是只读的。这是我保存图像的代码:
-(void)banner:(NSString *)path{
NSData * imageData = [[NSData alloc] initWithContentsOfURL: [NSURL URLWithString: path]];
UIImage *image = [UIImage imageWithData: imageData];
NSString* resourcePath = [[NSBundle mainBundle] resourcePath];
NSString* pathEnd = [resourcePath stringByAppendingFormat:@"/banner.png"];
NSData *data1 = [NSData dataWithData:UIImagePNGRepresentation(image)];
NSError *writeError = nil;
[data1 writeToFile:pathEnd options:NSDataWritingAtomic error:&writeError];
}
但是当我检索图像时,它不在该文件夹中。我能做些什么?
你不能,应用程序包是只读的。您应该将所有数据保存在文档或缓存目录中。
-(void)banner:(NSString *)path{
NSData * imageData = [[NSData alloc] initWithContentsOfURL: [NSURL URLWithString: path]];
UIImage *image = [UIImage imageWithData: imageData];
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSCachesDirectory, NSUserDomainMask, YES);
NSString *filePath = [[paths objectAtIndex:0] stringByAppendingPathComponent:@"banner.png"];
NSData *data1 = [NSData dataWithData:UIImagePNGRepresentation(image)];
NSError *writeError = nil;
[data1 writeToFile:filePath options:NSDataWritingAtomic error:&writeError];
if (writeError) {
NSLog(@"Error writing file: %@", writeError);
}
}
是否有任何理由先将数据转换为图像,然后再转换回图像NSData
又反对?
如果没有,你可以这样做:
-(void)banner:(NSString *)path{
NSData * imageData = [[NSData alloc] initWithContentsOfURL: [NSURL URLWithString: path]];
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSCachesDirectory, NSUserDomainMask, YES); NSString *filePath = [[paths objectAtIndex:0] stringByAppendingPathComponent:@"banner.png"];
NSError *writeError = nil;
[imageData writeToFile:filePath options:NSDataWritingAtomic error:&writeError];
if (writeError) {
NSLog(@"Error writing file: %@", writeError);
}
}
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