我正在尝试用 C++ 编写一个程序,模拟大学招生系统,学生输入他们的 ID,程序在文本文件中搜索他们的信息,并根据文本文件加载结构。我已经到了无法将他们注册的课程放入结构数组的地步。使用 getline 函数,使用“,”作为 delim 也将继续下一行,直到下一个逗号。正确的算法是什么?
这是包含以下内容的文件设置fake学生信息:
- 918273645,史蒂夫,奥尔布赖特,ITCS2530,数学210,ENG140
- 123456789,金,墨菲,ITCS2530,数学101
- 213456789,迪恩·鲍尔斯,ITCS2530,ENG140
- 219834765,杰瑞,克拉克,MGMT201,数学210
(为布局添加了项目符号;不在文件中)
例如,用户输入“123456789”作为其 ID,然后读取 Kim Murphy 的信息。在第一次迭代 getline 时,“ITCS2530”被读取并放入变量中,然后加载到结构中;没问题。但是,列表中的最后一个课程在下一个逗号之前有换行符,因此下一次迭代读取“MATH101/nl213456789”并将整个字符串放入变量中并尝试将其加载到结构中。
第一列是他们的 ID,然后是他们的名字、姓氏,最后是他们当前注册的课程。请注意,注册课程的数量可能会有所不同。
这是我目前正在处理的代码:
student login()
{
string ID;
student newStudent;
string enrolled;
int i = 0;
while (true)
{
cout << "Enter Student ID: ";
cin >> newStudent.ID;
cout << endl;
if (newStudent.ID.length() == 9)
break;
else
cout << "That ID is invalid - IDs are 9 digits" << endl;
}
ifstream inFile;
ofstream outFile;
inFile.open("registration.txt");
if (inFile.is_open())
//Check if file is open
{
while (!inFile.eof())
//While not at end of file
{
getline(inFile, ID, ',');
//Search for ID
if (ID == newStudent.ID)
{
getline(inFile, newStudent.fName, ',');
//Assign fName and lName
getline(inFile, newStudent.lName, ',');
while (enrolled != "\n")
{
getline(inFile, enrolled, ',');
if (enrolled == "\n")
{
cout << "Not currently enrolled in a class." << endl;
}
else
{
newStudent.courses[i] = enrolled;
i++;
}
}
cout << newStudent.lName << ", Welcome to the MCC Enrollment System!" << endl;
for (i = 0; i <= NUM_OF_COURSES; i++)
{
cout << "Enrolled courses: " << newStudent.courses[i] << endl;
}
cout << endl;
break;
//Stops searching
}
else
//Ignores rest of line - used to skip to the next line
{
getline(inFile, ID, '\n');
}
if (inFile.eof())
//If ID was not found
{
inFile.close();
cout << "Enter First Name: ";
//Begin entry of new student
cin >> newStudent.fName;
cout << endl;
cout << "Enter Last Name: ";
cin >> newStudent.lName;
cout << endl;
outFile.open("registration.txt", ios::app);
if (outFile.is_open())
{
outFile << newStudent.ID << "," << newStudent.fName << "," << newStudent.lName << "\n";
}
}
}
}
return newStudent;
}
预先感谢您的任何帮助。