cat >file1.sh <<'EOF_FILE1'
echo 'before source'
source 'file2.sh'
echo 'after source'
func1
EOF_FILE1
cat >file2.sh <<'EOF_FILE2'
echo 'test script'
func1() {
echo 'func1 starts'
exit
}
exit
EOF_FILE2
bash file1.sh
预期输出是：
before source
test script
after source
func1 starts
实际输出是：
before source
test script
由于以下原因，“后源”丢失exit命令。有没有办法解决这个问题，因为我无法删除exit从代码中？
鉴于best方法是编写旨在获取而不是执行时考虑到该用例的脚本，如果您出于某种原因无法这样做，您可能会考虑aliasing exit to return之前source命令，如下：
shopt -s expand_aliases # enable alias expansion (off by default in noninteractive shells)
alias exit=return # ...and alias 'exit' to 'return'
source 'file2.sh' # source in your file which incorrectly uses 'exit' at top-level
unalias exit # disable the alias...
echo 'after source'
func1
如果你想要exit为了在调用该函数时仍然生效，事情可以变得更复杂一些：
maybe_exit() {
local last_retval=$? # preserve exit's behavior of defaulting to $?
[[ $do_not_really_exit ]] && return # abort if flag is set
(( $# )) && exit "$@" # if arguments are given, pass them through
exit "$last_retval" # otherwise, use the $? we captured above
}
shopt -s expand_aliases # enable alias expansion (off by default in noninteractive shells)
alias exit=maybe_exit # ...and alias 'exit' to 'maybe_exit'
do_not_really_exit=1 # set a flag telling maybe_exit not to really exit
source 'file2.sh' # source in your file which incorrectly uses 'exit' at top-level
unset do_not_really_exit # clear that flag...
unalias exit # disable the alias...
echo 'after source'
func1
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