Python Selenium Javascript链接点击无法执行

我将 Selenium for Python 与 PhantomJS Ghost 驱动程序一起使用，以便单击 href 中包含 Javascript 的链接，例如来自this https://structuredginniemaes.ginnienet.com/Download/关联。我可以很好地获取链接作为一个元素，但是当我尝试单击它时，事情就会出错。这是一些代码（注意 - url 是一个列表，其中第一个元素是 Jscript 链接，第二个元素是链接文本）

def get_jscript_down(self,url):
    driver = webdriver.PhantomJS()
    print(self.exact_url)
    driver.get(self.exact_url)
    elements = driver.find_elements_by_tag_name("a")
    for ele in elements:
        if ele.text == url[1].encode("utf-8").replace("  "," "):
            break
    ele.click()
    print("Cannot yet download %s" % url)

    return False

除了 ele.click() 之外，一切都按我需要的方式工作。当我执行该命令时，我得到一个难看的 WebDriverException。

selenium.common.exceptions.WebDriverException: Message: u'Error Message => \'Click failed: ReferenceError: Can\'t find variable: __doPostBack\'\n caused by Request => {"headers":{"Accept":"application/json","Accept-Encoding":"identity","Connection":"close","Content-Length":"81","Content-Type":"application/json;charset=UTF-8","Host":"127.0.0.1:34441","User-Agent":"Python-urllib/2.6"},"httpVersion":"1.1","method":"POST","post":"{\"sessionId\": \"71c20b50-ca21-11e2-a03c-f58c49e5a1bc\", \"id\": \":wdc:1370025577147\"}","url":"/click","urlParsed":{"anchor":"","query":"","file":"click","directory":"/","path":"/click","relative":"/click","port":"","host":"","password":"","user":"","userInfo":"","authority":"","protocol":"","source":"/click","queryKey":{},"chunks":["click"]},"urlOriginal":"/session/71c20b50-ca21-11e2-a03c-f58c49e5a1bc/element/%3Awdc%3A1370025577147/click"}' ; Screenshot: available via screen

我不太确定为什么这次点击失败。据我所读，我应该可以以这种方式使用 click 。下面是堆栈跟踪的相关部分（从事情开始崩溃之前到结束）

line 283, in get_jscript_down
    ele.click()
  File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webelement.py", line 54, in click
    self._execute(Command.CLICK_ELEMENT)
  File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webelement.py", line 228, in _execute
    return self._parent.execute(command, params)
  File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webdriver.py", line 165, in execute
    self.error_handler.check_response(response)
  File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/errorhandler.py", line 158, in check_response
    raise exception_class(message, screen, stacktrace)
  

任何想法将不胜感激。我很困惑。

单击“Privatperson”时出现同样的错误这一页 http://dustin.no。该按钮的 ID 为“btnSelectB2C”。我最终做的是在元素上使用提交：

driver.find_element(:id, 'btnSelectB2C').submit

（这是 Ruby 代码，但我认为如果它适用于您的情况，调整起来应该很简单。）