使用两个具有相同字符的分解对象断言 True

我有两个 unicode 字符，两者具有相同的含义。这compat字符是对origin字符，这有意义，两者应该是相同的值，但是当我试图断言它们与条件相等时，它会返回False反而。

origin = 'ᅢ'  # korean letter for: AE
compat = 'ㅐ'  # korean letter for: AE

print('origin', ascii(origin))
print('compat', ascii(compat), '\n')

decompose_origin = unicodedata.decomposition(origin)
decompose_compat = unicodedata.decomposition(compat)

print('decompose: origin', decompose_origin)
print('decompose: compat', decompose_compat, '\n')

# expected output: True
print(decompose_origin == decompose_compat)

origin '\u1162'
compat '\u3150'

decompose: origin
decompose: compat <compat> 1162

False

将字符串标准化为NFKC or NFKD正常形式 https://docs.python.org/3/library/unicodedata.html#unicodedata.normalize使它们具有可比性：

from unicodedata import normalize

origin = '\u1162'
compat = '\u3150'
for normal_form in ('NFC', 'NFD', 'NFKC', 'NFKD'):
    print(normal_form, ascii(normalize(normal_form, origin + ' == ' + compat)))
    print(normalize(normal_form, origin) == normalize(normal_form, compat))
# NFC '\u1162 == \u3150'
# False
# NFD '\u1162 == \u3150'
# False
# NFKC '\u1162 == \u1162'
# True
# NFKD '\u1162 == \u1162'
# True

Both NFKC and NFKD执行“兼容性分解，即用其等效字符替换所有兼容性字符”。这NFKC范式也适用规范组合。