Jmeter JSR223 Sampler - 无法将数据写入 CSV 文件

我正在使用 Jmeter v4.0 r1823414。根据这个答案 https://stackoverflow.com/questions/50820389/unable-to-set-incremental-variable-in-jmeter?noredirect=1#comment88652169_50822368，有一个使用 JSR223 PostProcessor 的建议，逐字：

建议考虑使用 Groovy 进行任何形式的脚本编写 迁移到 JSR223 后处理器

在这种方法之前，我尝试使用 BeanShell Sampler 将数据简单地写入 csv 文件。我从以下位置获取的代码示例火焰计教程 https://www.blazemeter.com/blog/saving-data-to-csv-files-with-java-through-jmeter页。但是，我收到了错误

Sourced file: inline evaluation of: ``import java.io.FileWriter; import java.util.Arrays; import java.io.Writer; impor . . . '' : Typed variable declaration : Attempt to access property on undefined variable or class name

好吧，既然有人建议搬到JSR223采样器（或者PostProcessor，不确定它们在功能方面有什么区别），我稍微修改了代码，使其更加基于Java，以便在JSR223采样器:

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:/TiredOfProgramming/Work/results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            log.info(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        log.info(stringBuilder.toString());
        writer.append(stringBuilder.toString());
    }

        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);

        //proper close to file
        fileWriter.flush();
        fileWriter.close();
}

此特定脚本失败并显示以下消息：

Script8.groovy: 15: 意外标记：hello @ 第 15 行，第 39 列。 private static String[] params = {"hello", "world", "jmeter"};

如果我测试这个智能集成开发环境只需将 writeLine 方法包装到 main 方法中，一切正常

package com.tiredofprogramming;

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    public static void main(String[] args) throws IOException {
        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);
        //proper close to file
        fileWriter.flush();
        fileWriter.close();
    }


    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            System.out.println(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        System.out.println(stringBuilder.toString());
        writer.append(stringBuilder.toString());

  }
}

我的问题是：groovy 采样器是否理解 Java（在一篇 SO 帖子中我看到提到 Groovy 理解 99% 的 java 语法）。有人曾经成功使用 Jmeter 将数据写入 csv 文件吗？

尝试一下这个小小的修改：

//Default separator
char SEPARATOR = ',';

//get path of csv file (creates new one if its not exists)
String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

def params = ["hello", "world", "jmeter"];

//function write line in csv
def writeLine(FileWriter writer, List<String> parameters, char separator) throws IOException {
    boolean firstParameter = true;
    StringBuilder stringBuilder = new StringBuilder();
    String parameter = " ";

    for (int i = 0; i < parameters.size(); i++) {
        //get param
        parameter = parameters[i];
        log.info(parameter);

        //if the first param in the line, separator is not needed
        if (!firstParameter) {
            stringBuilder.append(separator);
        }

        //Add param to line
        stringBuilder.append(parameter);

        firstParameter = false;
    }

    //prepare file to next line
    stringBuilder.append("\n");

    //add to file the line
    log.info(stringBuilder.toString());
    writer.append(stringBuilder.toString());
}

FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);

//proper close to file
fileWriter.flush();
fileWriter.close();

然而，在 Groovy 中还有更简单的方法可以实现相同的目的，请查看：

• Groovy 的优点：处理文件 http://mrhaki.blogspot.com/2009/08/groovy-goodness-working-with-files.html
• Apache Groovy - 为什么以及如何使用它 https://www.blazemeter.com/blog/groovy-new-black