edit:
我花了很长时间，但这是我想到的：
function replaceLinks($replacements, $string){
foreach($replacements as $key=>$val){
$key=strtolower((string)$key);
$newReplacements[$key]=array();
$newReplacements[$key]['id']=$val;
//strings to make sure the search isn't in front of
$newReplacements[$key]['behinds']=array();
//strings to make sure the search isn't behind
$newReplacements[$key]['aheads']=array();
//check for other searches this is a substring of
foreach($replacements as $key2=>$val2){
$key2=(string)$key2;
/*
//debugging
$b = ($key=='11 22'&&$key2=='11 22 33');
if($b){
l('strlen $key2: '.strlen($key2));
l('strlen $key: '.strlen($key));
l('strpos: '.(strpos($key2,$key)));
}
*/
//the second search is longer and the first is a substring of it
if(strlen($key2)>strlen($key) && ($pos=strpos($key2,$key))!==false){
//the first search isn't at the start of the second search ('the ford' and 'ford')
if($pos!=0){
$newReplacements[$key]['behinds'][]=substr($key2,0,$pos);
}
//it's not at the end ('ford' and 'fords')
if(($end=$pos+strlen($key))!=strlen($key2)){
$newReplacements[$key]['aheads'][]=substr($key2,$end);
}
}
}
}
foreach($newReplacements as $key=>$item){
//negative lookbehind for words or >
$tmp="/(?<![\w>=])";
//negative lookbehinds for the beginnings of other searches that this search is a subtring of
foreach($item['behinds'] as $b){
$tmp.="(?<!$b)";
}
//the actual search
$tmp.="($key)";
//negative lookaheads for ends of other searches that this is a substring of.
foreach($item['aheads'] as $a){
$tmp.="(?!$a)";
}
//case insensitive
$tmp.='/ie';
$replacementMatches[]=$tmp;
}
return preg_replace($replacementMatches,'"<a href=\"".$newReplacements[strtolower("$1")]["id"]."\">$1</a>"' ,$string);
}
向其传递一个数组，例如您正在讨论的数组：
$replaceWith = array('ford mustang'=>123,'ford'=>42,'honda'=>324);
和一个字符串：
$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";
echo replaceLinks($replaceWith,$string);
它优先考虑较大的字符串键，因此如果您有ford and ford mustang，它将取代ford mustang与链接。
Not very practical, but might work.
$string = "That is a very nice ford mustang, if only every other ford was quite as nice as this honda";
$remove = array("/(?<![\w>])ford mustang(?![\w<])/",'/(?<![>\w])ford(?! mustang)(?![<\w])/',"/(?<![>\w])honda(?![<\w])/");
$replaceWith = array("<a href='fordmustangID'>ford mustang</a>","<a href='fordID'>ford</a>","<a href='hondaID'>honda</a>");
echo preg_replace($remove, $replaceWith,$string);
我使用带有负向前查找和向后查找的正则表达式来确保我们要替换的字符串部分不是字母数字序列的一部分（例如12ford23 or afford) 或触摸元素的开始或结束标记。
