Python实例7:七段数码管绘制
基本思路:
- 绘制单个数字对应的数码管;
- 获得一串数字,绘制对应的数码管;
- 获取当前系统时间,绘制对应的数码管;
步骤:
- 七段数码管由7个基本线条组成;可以有固定顺序;显示不同的线条;
- 获取一段数字,绘制多个数码管;
- 获取当前时间,以使用数码管显示时间;
import turtle, time
def drawGap():
turtle.penup()
turtle.fd(5)
def drawLine(draw):
drawGap()
turtle.pendown() if draw else turtle.penup()
turtle.fd(40)
drawGap()
turtle.right(90)
def drawDigit(digit):
drawLine(True) if digit in [2,3,4,5,6,8,9] else drawLine(False)
drawLine(True) if digit in [0,1,3,4,5,6,7,8,9] else drawLine(False)
drawLine(True) if digit in [0,2,3,5,6,8,9] else drawLine(False)
drawLine(True) if digit in [0,2,6,8] else drawLine(False)
turtle.left(90)
drawLine(True) if digit in [0,4,5,6,8,9] else drawLine(False)
drawLine(True) if digit in [0,2,3,5,6,7,8,9] else drawLine(False)
drawLine(True) if digit in [0,1,2,3,4,7,8,9] else drawLine(False)
turtle.left(180)
turtle.penup()
turtle.fd(20)
def drawDate(date):
turtle.pencolor("red")
for i in date:
if i == '-':
turtle.write('年',font=("Arial",18,"normal"))
turtle.pencolor("green")
turtle.fd(40)
elif i == '=':
turtle.write('月',font=("Arial",18,"normal"))
turtle.pencolor("blue")
turtle.fd(40)
elif i == '+':
turtle.write('日',font=("Arial",18,"normal"))
else:
drawDigit(eval(i))
def main():
turtle.setup(800, 350, 200, 200)
turtle.penup()
turtle.fd(-300)
turtle.pensize(5)
drawDate(time.strftime('%Y-%m=%d+',time.gmtime()))
turtle.hideturtle()
turtle.done()
main()
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