struct LatLng {
let latitude: Double
let longitude: Double
func getJSON() -> NSMutableDictionary {
let dict = NSMutableDictionary()
dict.setValue(latitude, forKey: "latitude")
dict.setValue(longitude, forKey: "longitude")
return dict
}
}
struct Field {
var name: String
var center: LatLng
var perimeter: [LatLng]
func getJSON() -> NSMutableDictionary {
let values = NSMutableDictionary()
var perimeterArray = Array<NSMutableDictionary>()
for item in perimeter {
perimeterArray.append(item.getJSON())
}
values.setValue(name, forKey: "name")
values.setValue(center.getJSON(), forKey: "center")
values.setValue(perimeterArray, forKey: "perimeter")
return values
}
}
let peri = [LatLng(latitude: 10.0, longitude: 10.0), LatLng(latitude: 20.0, longitude: 20.0)]
let center = LatLng(latitude: 15.0, longitude: 15.0)
let field = Field(name: "test", center: center, perimeter: peri)
let json = try NSJSONSerialization.dataWithJSONObject(field.getJSON(), options: .PrettyPrinted)
let jsonString = NSString(data: json, encoding: NSUTF8StringEncoding)
print(jsonString)
//PRINTS THE FOLLOWING OUTPUT
Optional({
"name" : "test",
"center" : {
"longitude" : 15,
"latitude" : 15
},
"perimeter" : [{
"longitude" : 10,
"latitude" : 10
},
{
"longitude" : 20,
"latitude" : 20
}]
})
UPDATE
为了序列化 Field 对象的数组,您可以执行类似的操作。
let field1 = Field(name: "value1", center: center, perimeter: peri)
let field2 = Field(name: "value2", center: center, perimeter: peri)
let field3 = Field(name: "value3", center: center, perimeter: peri)
let fieldArray = [field1.getJSON(), field2.getJSON(), field3.getJSON()]
let json = try NSJSONSerialization.dataWithJSONObject(fieldArray, options: .PrettyPrinted)
let jsonString = NSString(data: json, encoding: NSUTF8StringEncoding)
请注意,这只是一种快速解决方案,而不是最好的解决方案。这只是为了让您了解它将如何进行。我确信你能够在这方面有所改进。