C++ 匹配文件中的字符串并获取行号

我有一个包含前 1000 个婴儿名字的文件。我想询问用户一个名字...搜索文件...并告诉用户该名字对于男孩名字的排名以及女孩名字的排名。如果它不是男孩名字或女孩名字，它会告诉用户它不属于该性别的流行名字。

该文件的布局如下：

Rank Boy-Names Girl-Names
1    Jacob     Emily
2    Michael   Emma
.
.
.

输入所需的输出Michael将会：

迈克尔是男孩名字中第二受欢迎的名字。

如果迈克尔不是女孩的名字，则应该说：

迈克尔并不是最受欢迎的女孩名字之一

但如果是的话，它会说：

迈克尔是（排名）女孩名字之一

到目前为止我的代码如下..我似乎无法弄清楚。谢谢你的帮助。

#include <iostream>
#include <fstream>
#include <string>
#include <cctype>
using namespace std;
void find_name(string name);

int main(int argc, char **argv)
{
    string name;
    cout << "Please enter a baby name to search for:\n";
    cin >> name;
    /*while(!(cin>>name))
    {
        cout << "Please enter a baby name to search for:\n";
        cin >> name;
    }*/
    find_name(name);

    cin.get();
    cin.get();
    return 0;
}

void find_name(string name)
{
    ifstream input;
    int line = 0;
    string line1 = " ";
    int rank;
    string boy_name = "";
    string girl_name = "";
    input.open("/<path>/babynames2004.rtf");
    if (!input)
    {
        cout << "Unable to open file\n";
        exit(1);
    }

    while(input.good())
    {
        while(getline(input,line1))
        {
            input >> rank >> boy_name >> girl_name;
            if (boy_name == name)
            {
                cout << name << " is ranked " << rank << " among boy names\n";
            }
            else
            {
                cout << name << " is not among the popular boy names\n";
            }
            if (girl_name == name)
            {
                cout << name << " is ranked " << rank << " among girl names\n"; 
            }
            else
            {
                cout << name << " is not among the popular girl names\n";
            }
        }
    }
    input.close();
}

在你扫描完列表之前，你就已经承认失败了（“X 不在流行的 Y 名字之列”）。一个很好的简单方法（如果不是最有效的话）是在宣布没有匹配项之前记住排名直到列表末尾。像这样的事情：

bool boyrank = false, girlrank = false;

while(getline(input,line1))
{
  input >> rank >> boy_name >> girl_name;
  if (boy_name == name)
    {
      cout << name << " is ranked " << rank << " among boy names\n";
      boyrank = true;
    }

  if (girl_name == name)
    {
      cout << name << " is ranked " << rank << " among girl names\n";
      girlrank = true;
    }
}

if(boyrank == false)
{
  cout << name << " is not among the popular boy names\n";
}
if(girlrank == false)
{
  cout << name << " is not among the popular girl names\n";
}