如何为 2 个不同的团队在两条线上获得正确数量的 count() ？ （计算进球数）

我正在尝试编写的代码应该读取文本文件，并检查“EASTS”或“WESTS”得分了多少次，我可以使用 find 和“EASTS”或“WESTS”来获取数字。 但我不是得到出现的次数，而是得到它在每行中存在的次数。

So:

1 
 1
 1
 1

（我不知道为什么在属于西方的 1 之前有空格）

正文如下：

EASTS versus WESTS
EASTS have scored 25:13
WESTS have scored 26:38
WESTS have scored 40:23
WESTS have scored 42:01

这是我的代码，我做错了什么？

name = "scores.txt"

with open(name) as f:
    ff = f.readlines()[1:]
    for line in ff:
        words = line.split()
        a = words.count('EASTS')
        b = words.count('WESTS')
        a_ = str(a)
        b_ = str(b)
        eas =  a_.strip('0')
        wes =  b_.strip('0')
        print(eas, wes)

结果应该是这样的

WESTS 3
EASTS 1

有人可以帮忙吗？先感谢您！

初始化变量（wests, easts) 为 0。在循环中加 1。打印结果。

import itertools

team1, team2 = 'WESTS', 'EASTS'
count1, count2 = 0, 0
with open('scores.txt') as f:
    for line in itertools.islice(f, 1, None):
        if line.startswith(team1):
            count1 += 1
        else:
            count2 += 1
    print(team1, count1)
    print(team2, count2)

在运行时获取团队名称

with open('scores.txt') as f:
    team1, _, team2 = next(f).split()
    count1, count2 = 0, 0
    for line in f:
        if line.startswith(team1):
            count1 += 1
        else:
            count2 += 1
    print(team1, count1)
    print(team2, count2)