使用 Roslyn，如何枚举 Visual Basic 文档中的成员（命名空间、类等）详细信息？

使用 Roslyn，确定 Visual Basic 文档成员的唯一机制似乎是：

var members = SyntaxTree.GetRoot().DescendantNodes().Where(node =>
      node is ClassStatementSyntax ||
      node is FunctionAggregationSyntax ||
      node is IncompleteMemberSyntax ||
      node is MethodBaseSyntax ||
      node is ModuleStatementSyntax ||
      node is NamespaceStatementSyntax ||
      node is PropertyStatementSyntax ||
      node is SubNewStatementSyntax
    );

如何获得会员name, StarLineNumber and EndLineNumber每个成员的？

不仅存在一种获得它的方法：

1）当你尝试时：我不会向所有善良的成员展示这种方式（他们的数量很大并且逻辑是相似的），但只展示其中的一个，例如ClassStatementSyntax:

• 实现它的名字只是得到ClassStatementSyntax.Identifier.ValueText
• 要获得起始线，您可以使用Location作为方式之一：

var location = Location.Create(SyntaxTree, ClassStatementSyntax.Identifier.Span);
var startLine = location.GetLineSpan().StartLinePosition.Line;

• 检索结束行的逻辑看起来像接收开始行的逻辑，但它依赖于相应的结束语句（某种结束语句或 self）

2）更有用的方式——使用SemanticModel获取您想要的数据： 通过这种方式，您将只需要接收语义信息ClassStatementSyntax, ModuleStatementSyntxt and NamespaceStatementSyntax，只需致电即可收到他们的所有成员GetMembers():

...

  SemanticModel semanticModel = // usually it is received from the corresponding compilation
  var typeSyntax = // ClassStatementSyntax, ModuleStatementSyntxt or NamespaceStatementSyntax
  string name = null;
  int startLine;
  int endLine;

  var info = semanticModel.GetSymbolInfo(typeSyntax);
  if (info.Symbol is INamespaceOrTypeSymbol typeSymbol)
  {
      name = typeSymbol.Name; // retrieve Name
      startLine = semanticModel.SyntaxTree.GetLineSpan(typeSymbol.DeclaringSyntaxReferences[0].Span).StartLinePosition.Line; //retrieve start line
      endLine = semanticModel.SyntaxTree.GetLineSpan(typeSymbol.DeclaringSyntaxReferences[0].Span).EndLinePosition.Line; //retrieve end line
      foreach (var item in typeSymbol.GetMembers())
      {
          // do the same logic for retrieving name and lines for all others members without calling GetMembers()
      }
  }
  else if (semanticModel.GetDeclaredSymbol(typeSyntax) is INamespaceOrTypeSymbol typeSymbol2)
  {
      name = typeSymbol2.Name; // retrieve Name
      startLine = semanticModel.SyntaxTree.GetLineSpan(typeSymbol2.DeclaringSyntaxReferences[0].Span).StartLinePosition.Line; //retrieve start line
      endLine = semanticModel.SyntaxTree.GetLineSpan(typeSymbol2.DeclaringSyntaxReferences[0].Span).EndLinePosition.Line; //retrieve end line

      foreach (var item in typeSymbol2.GetMembers())
      {
          // do the same logic for retrieving name and lines for all others members without calling GetMembers()
      }
  }

但请注意，当您有部分声明时，您的DeclaringSyntaxReferences会有几个项目，所以你需要过滤SyntaxReference按你当前的SyntaxTree