我有一个设置如下的函数
function mainFunction() {
function subFunction() {
var str = "foo";
return str;
}
}
var test = mainFunction();
alert(test);
按照我的逻辑,该警报应该返回“foo”,但它返回未定义。我究竟做错了什么?
UPDATE:这是我的实际代码(它是使用 Google API 进行反向地理编码的函数)
function reverseGeocode(latitude,longitude){
var address = "";
var country = "";
var countrycode = "";
var locality = "";
var geocoder = new GClientGeocoder();
var latlng = new GLatLng(latitude, longitude);
return geocoder.getLocations(latlng, function(addresses) {
address = addresses.Placemark[0].address;
country = addresses.Placemark[0].AddressDetails.Country.CountryName;
countrycode = addresses.Placemark[0].AddressDetails.Country.CountryNameCode;
locality = addresses.Placemark[0].AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.LocalityName;
return country;
});
}
你必须先调用一个函数,然后它才能返回任何内容。
function mainFunction() {
function subFunction() {
var str = "foo";
return str;
}
return subFunction();
}
var test = mainFunction();
alert(test);
Or:
function mainFunction() {
function subFunction() {
var str = "foo";
return str;
}
return subFunction;
}
var test = mainFunction();
alert( test() );
对于您的实际代码。返回应该在主函数之外。回调在内部某处被调用getLocations
方法,因此它的返回值不会在您的主函数中收到。
function reverseGeocode(latitude,longitude){
var address = "";
var country = "";
var countrycode = "";
var locality = "";
var geocoder = new GClientGeocoder();
var latlng = new GLatLng(latitude, longitude);
geocoder.getLocations(latlng, function(addresses) {
address = addresses.Placemark[0].address;
country = addresses.Placemark[0].AddressDetails.Country.CountryName;
countrycode = addresses.Placemark[0].AddressDetails.Country.CountryNameCode;
locality = addresses.Placemark[0].AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.LocalityName;
});
return country
}
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