嗨，我有一个字符串，我想使用正则表达式或任何方法来打破它
我的字符串是
1 Agra Achhnera NIL
2 Agra Agra NIL
3 Agra Fatehabad NIL
4 Agra Fatehpur Sikri NIL
5 Aligarh Aligarh 1300.00
6 Aligarh Khair 1300.00
7 Ambedkar Nagar Akbarpur NIL
8 Ambedkar Nagar Tanda Akbarpur 1478.00
结果我想要这样的字符串：-
1 Agra Achhnera NIL
2 Agra Agra NIL
3 Agra Fatehabad NIL
4 Agra FatehpurSikri NIL
5 Aligarh Aligarh 1300.00
6 Aligarh Khair 1300.00
7 AmbedkarNagar Akbarpur NIL
18 AmbedkarNagar TandaAkbarpur 1478.00
我怎样才能做到这一点
我的java代码
<%@page import="com.gargoylesoftware.htmlunit.BrowserVersion;"%>
<%@page import="org.openqa.selenium.By;"%>
<%@page import="org.openqa.selenium.WebDriver;"%>
<%@page import="org.openqa.selenium.WebElement"%>
<%@page import="org.openqa.selenium.firefox.FirefoxDriver"%>
<%@page import="org.openqa.selenium.htmlunit.HtmlUnitDriver"%>
<%@page import="org.openqa.selenium.support.ui.Select"%>
<%
WebDriver driver = new HtmlUnitDriver(BrowserVersion.getDefault());
String sDate = "27/03/2014";
String url="http://www.upmandiparishad.in/commodityWiseAll.aspx";
driver.get(url);
Thread.sleep(5000);
new Select(driver.findElement(By.id("ctl00_ContentPlaceHolder1_ddl_commodity"))).selectByVisibleText("Jo");
driver.findElement(By.id("ctl00_ContentPlaceHolder1_txt_rate")).sendKeys(sDate);
Thread.sleep(3000);
driver.findElement(By.id("ctl00_ContentPlaceHolder1_btn_show")).click();
Thread.sleep(5000);
WebElement findElement = driver.findElement(By.id("ctl00_ContentPlaceHolder1_GridView1"));
String htmlTableText = findElement.getText();
// do whatever you want now, This is raw table values.
htmlTableText=htmlTableText.replace("S.No.DistrictMarketPrice","");
htmlTableText= htmlTableText.replaceAll("\\s(\\d+\\s[A-Z])", "<br>$1");
//System.out.println(htmlTableText);
String data[]=htmlTableText.split("");
out.println(data[9]);
driver.close();
driver.quit();
%>
提前致谢
这将适用于您的特定情况，因为您正在抓取的数据采用这种格式，并且以下正则表达式在大多数情况下都适用。我并不是说这是完美的答案，但我应该告诉你，这会让你继续前进：
find
[a-z]\s[A-Z]
并替换为\1\2
演示在这里：http://regex101.com/r/kF8vG6 http://regex101.com/r/kF8vG6
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