我正在尝试一个简单的程序,如果移动的话,它会发出声音。所以一开始我就下了 - 播放声音 1,从那时起,每一个动作都会持续播放声音。在计数 4 时,我已经从头开始播放了。
问题是:当我不移动手指并将其放在同一个地方时,声音仍然保持 1 x 1 - 计算出 x 和 y 值触发。我该如何阻止这个?
OnTouchListener MyOnTouchListener= new OnTouchListener()
{
public boolean onTouch(View view, MotionEvent event)
{
switch(event.getAction() & MotionEvent.ACTION_MASK)
{
case MotionEvent.ACTION_DOWN:
x = (int) event.getX();
y = (int) event.getY();
oldval = x+y;
break;
case MotionEvent.ACTION_MOVE:
{
Log.e("X value", "X is "+x);
Log.e("Y value", "Y is "+y);
try
{
Thread.sleep(500);
} catch (InterruptedException e) {
}
int newval= (int) (event.getX() + event.getY());
if(Math.abs(oldval-newval)>50)
{
Log.e("First", "next button");
longpressCount++;
if(longpressCount==1)
{
Log.e("1", "BUTTON PRESSED");
}
else if(longpressCount==2)
{
Log.e("2", "BUTTON PRESSED");
}
else if(longpressCount==3)
{
Log.e("3", "BUTTON PRESSED");
}
else if(longpressCount==4)
{
Log.e("4", "BUTTON PRESSED");
longpressCount = 0;
}
}
break;
}
}
return true;
}
MOVE 非常灵敏,只要您的手指按下,就会继续调用。在声音播放代码末尾设置旧值,这样只有从该位置再移动 50 距离时才会播放。
像这样的东西。
OnTouchListener MyOnTouchListener= new OnTouchListener()
{
public boolean onTouch(View view, MotionEvent event)
{
switch(event.getAction() & MotionEvent.ACTION_MASK)
{
case MotionEvent.ACTION_DOWN:
x = (int) event.getX();
y = (int) event.getY();
oldval = x+y;
break;
case MotionEvent.ACTION_MOVE:
{
Log.e("X value", "X is "+x);
Log.e("Y value", "Y is "+y);
try
{
Thread.sleep(500);
} catch (InterruptedException e) {
}
int newval= (int) (event.getX() + event.getY());
if(Math.abs(oldval-newval)>50)
{
Log.e("First", "next button");
longpressCount++;
if(longpressCount==1)
{
Log.e("1", "BUTTON PRESSED");
}
else if(longpressCount==2)
{
Log.e("2", "BUTTON PRESSED");
}
else if(longpressCount==3)
{
Log.e("3", "BUTTON PRESSED");
}
else if(longpressCount==4)
{
Log.e("4", "BUTTON PRESSED");
longpressCount = 0;
}
oldval = event.getX() + event.getY();
}
break;
}
}
return true;
}
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