"a004-1b","North","at006754"
"a004-1c","south","atytgh0"
"a004-1d","east","atrthh"
"a010-1a","midwest","atyu"
"a010-1b","south","rfg67"
我想打印第一列和第二列，没有任何额外的字符 我想消除所有（“”和第三列） 提前致谢
awk -F'^"|","|"$' '{print $2,$3}' ./infile.csv
上面的脚本甚至可以处理嵌入双引号或逗号的字段。唯一的缺点（如果你可以这样称呼它）是第一个字段从$2
概念验证
$ awk -F'^"|","|"$' '{print $2,$3}' ./infile.csv
a004-1b North
a004-1c south
a010-1a midwest
a010-1b south
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