我需要提取某个路径的父目录的名称。它看起来是这样的：
C:\stuff\directory_i_need\subdir\file.jpg
我想提取directory_i_need.
import os
## first file in current dir (with full path)
file = os.path.join(os.getcwd(), os.listdir(os.getcwd())[0])
file
os.path.dirname(file) ## directory of file
os.path.dirname(os.path.dirname(file)) ## directory of directory of file
...
您可以根据需要继续执行此操作多次......
Edit: from os.path http://docs.python.org/library/os.path.html，您可以使用 os.path.split 或 os.path.basename：
dir = os.path.dirname(os.path.dirname(file)) ## dir of dir of file
## once you're at the directory level you want, with the desired directory as the final path node:
dirname1 = os.path.basename(dir)
dirname2 = os.path.split(dir)[1] ## if you look at the documentation, this is exactly what os.path.basename does.
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