我正在研究这个问题here https://stackoverflow.com/questions/40691773/r-four-lattice-barcharts-side-by-side-in-2x2-window从 2x2 绘图的子图到整个窗口获取图例。目标是获取单个图例，然后删除其他图例，只有一个图例就足够了，并且应该位于整个窗格的右侧。
也许相关
- 使用 grid.arrange (gridExtra) 和基于点阵的图的全局图例 https://stackoverflow.com/questions/33346823/global-legend-using-grid-arrange-gridextra-and-lattice-based-plots
Code
require(lattice)
require(gridExtra)
f<-function(x) as.double(as.character(x)) #factors converted to vectors https://stackoverflow.com/a/40680020/54964
data.female <- structure(list(N11.1 = structure(c(3L, 3L), .Label = c("", "0.0",
"1.0", "N11"), class = "factor"), N22.1 = structure(c(2L, 2L), .Label = c("",
"0.0", "2.0", "N22"), class = "factor"), N33.1 = structure(c(2L,
2L), .Label = c("", "0.0", "N33"), class = "factor"), N44.1 = structure(2:3, .Label = c("",
"0.0", "0.1", "0.2", "N44"), class = "factor"), N21.1 = structure(c(2L,
2L), .Label = c("", "0.0", "N21"), class = "factor"), N31.1 = structure(c(2L,
2L), .Label = c("", "0.0", "N31"), class = "factor"), N32.1 = structure(c(5L,
7L), .Label = c("", "0.0", "10.8", "11.0", "12.0", "17.0", "20.9",
"22.8", "24.0", "3.0", "4.0", "44.0", "N32"), class = "factor")), .Names = c("N11.1",
"N22.1", "N33.1", "N44.1", "N21.1", "N31.1", "N32.1"), row.names = c("Sinus",
"Arr/AHB"), class = "data.frame")
data.male <- structure(list(N11.1 = structure(c(3L, 3L), .Label = c("", "0.0",
"1.0", "N11"), class = "factor"), N22.1 = structure(c(2L, 2L), .Label = c("",
"0.0", "2.0", "N22"), class = "factor"), N33.1 = structure(c(2L,
2L), .Label = c("", "0.0", "N33"), class = "factor"), N44.1 = structure(c(2L,
2L), .Label = c("", "0.0", "0.1", "0.2", "N44"), class = "factor"),
N21.1 = structure(c(2L, 2L), .Label = c("", "0.0", "N21"), class = "factor"),
N31.1 = structure(c(2L, 2L), .Label = c("", "0.0", "N31"), class = "factor"),
N32.1 = structure(c(11L, 9L), .Label = c("", "0.0", "10.8",
"11.0", "12.0", "17.0", "20.9", "22.8", "24.0", "3.0", "4.0",
"44.0", "N32"), class = "factor")), .Names = c("N11.1", "N22.1",
"N33.1", "N44.1", "N21.1", "N31.1", "N32.1"), row.names = c("Sinus",
"Arr/AHB"), class = "data.frame")
ID<-c("Sinus","Arr/AHB")
tl <- "female"
p1 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
data=data.female,
auto.key=list(space='right'),
ylim=c(0,50),
beside=TRUE,
ylab = "Number of cases",
xlab = "Population/Sample",
main = tl
)
tl <- "male"
p2 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
data=data.male,
auto.key=list(space='right'),
ylim=c(0,50),
beside=TRUE,
ylab = "Number of cases",
xlab = "Population/Sample",
main = tl
)
# Just repeat two barcharts more to get 2x2 example
tl <- "female"
p3 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
data=data.female,
auto.key=list(space='right'),
ylim=c(0,50),
beside=TRUE,
ylab = "Number of cases",
xlab = "Population/Sample",
main = tl
)
tl <- "male"
p4 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
data=data.male,
auto.key=list(space='right'),
ylim=c(0,50),
beside=TRUE,
ylab = "Number of cases",
xlab = "Population/Sample",
main = tl)
grid.arrange(p1,p2,p3,p4, ncol=2, nrow=2,left=("LEFT TITLE"),right=("RIGHT"),bottom=("BOTTOM"), top=("TOP"))
编译生成上面的网格图，但由于图例，以下内容不起作用
grid.arrange(p1,p2,p3,p4, ncol=2, nrow=2,
legend=list(space='right',
text=c("N11.1","N22.1","N33.1","N44.1","N21.1","N31.1","N32.1"),
columns=1))
最简单的方法是继承一些子图的图例并使用类似的东西auto.key但我无法让这样的命令工作，因此尝试使用图例命令创建组对象。
legend 命令有什么问题，是否有任何方便的方法将子图的图例继承到整个窗格，以便 auto.key 可以在窗格的外部使用？
帮助问题
-
颜色如何从自动全局创建命令 auto.key 继承到图例？
-
您如何方便地从子图中获取图例标签（N11.1，N22.1，...），而不是手动编写图例标签？
