select count(*) as count from table
group by foreign_id order by count
这将返回每个外部 ID 的多个匹配项。然而,我正在寻找的是总结结果。
所以结果是:
10 results grouping 1 elements
5 results grouping 2 elements
7 results grouping 7 elements
好的,我知道了。问题的标题比问题本身更好地解释了它:)
首先需要知道每个FK出现了多少次:
select count(*) as GroupAmount from t1
group by foreign_id
一旦你有了这个,你必须将它们分组以获得每个项目出现的次数,方式与上面相同。这将导致:
select GroupAmount, count(*) GroupAmountTimes from (
select count(foreign_id) as GroupAmount from t1
group by foreign_id
) as SubQuery
group by GroupAmount
查看实际效果here http://sqlfiddle.com/#!2/35661/5
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