我的目标是推出一项能够满足所有应用程序网络需求的服务。
我想也许打开2个套接字用于数据传输。我希望异步处理数据，所以我想我应该在两个单独的线程中运行它们，每个线程针对每个套接字，这样数据就可以在两个不同的“链接”异步中进行流式传输。
所以，我希望有两件事：
更好的整体设计。也许我完全搞错了..
有人可以向我解释一下，一旦我需要将数据传递给主服务或从主服务传递数据，我如何与这些线程进行通信？据我所知（或）我需要使用信号:)（开玩笑..）
好吧，我可以说我终于明白了，就在放弃之前。这是一个超级简单的应用程序，它在活动内运行线程并处理双向通讯使用两个不同的处理程序对于每个实体！
代码：
public class MainActivity extends Activity {
//Properties:
private final String TAG = "Activity"; //Log tag
private MyThread mThread; //spawned thread
Bundle myB = new Bundle(); //used for creating the msgs
public Handler mHandler = new Handler(){ //handles the INcoming msgs
@Override public void handleMessage(Message msg)
{
myB = msg.getData();
Log.i(TAG, "Handler got message"+ myB.getInt("THREAD DELIVERY"));
}
};
//Methods:
//--------------------------
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mThread = new MyThread(mHandler);
mThread.start();
sendMsgToThread();
}
//--------------------------
void sendMsgToThread()
{
Message msg = mThread.getHandler().obtainMessage();
myB.putInt("MAIN DELIVERY", 321);
msg.setData(myB);
mThread.getHandler().sendMessage(msg);
}
}
//=========================================================================================
//=========================================================================================
public class MyThread extends Thread{
//Properties:
private final String TAG = "MyThread"; //Log tag
private Handler outHandler; //handles the OUTgoing msgs
Bundle myB = new Bundle(); //used for creating the msgs
private Handler inHandler = new Handler(){ //handles the INcoming msgs
@Override public void handleMessage(Message msg)
{
myB = msg.getData();
Log.i(TAG, "Handler got message"+ myB.getInt("MAIN DELIVERY"));
}
};
//Methods:
//--------------------------
public void run(){
sendMsgToMainThread(); //send to the main activity a msg
Looper.prepare();
Looper.loop();
//after this line nothing happens because of the LOOP!
Log.i(TAG, "Lost message");
}
//--------------------------
public MyThread(Handler mHandler) {
//C-tor that get a reference object to the MainActivity handler.
//this is how we know to whom we need to connect with.
outHandler = mHandler;
}
//--------------------------
public Handler getHandler(){
//a Get method which return the handler which This Thread is connected with.
return inHandler;
}
//--------------------------
private void sendMsgToMainThread(){
Message msg = outHandler.obtainMessage();
myB.putInt("THREAD DELIVERY", 123);
msg.setData(myB);
outHandler.sendMessage(msg);
}
}
//=========================================================================================
//=========================================================================================
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="test.test.namespace"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk android:minSdkVersion="10" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".MainActivity" android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
输出是：
01-26 06:25:40.683: I/Activity(19560): Handler got message123
01-26 06:25:40.683: I/MyThread(19560): Handler got message321
我在阅读 endian 提供的帖子时发现了这一点，here http://techtej.blogspot.com/2011/02/android-passing-data-between-main.html.
我希望其他人会发现这很有用。祝你好运：）
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
