C语言中如何将数组存入数组？

假设我有一个固定大小为 3 的数组，用于存储颜色的 RGB。 例子：

color[3] = {0, 0, 255}

我还有另一个数组 arrayOfColors 存储许多颜色。 例子：

arrayOfColors = { {0, 0, 255}, {0, 0, 0}, {255, 255, 255} } 

我不确定最好的方法是什么，但我已经尝试过。但当我采用这种方法时，我遇到了错误。请帮帮我，我对C语言很陌生。先感谢您！

unsigned char color1[3] = {0, 0, 0};
unsigned char color2[3] = {0, 255, 255};

unsigned char *rowColors = NULL;
rowColors = (unsigned char*)malloc((2) * sizeof(char));
rowColors[0] = color1;
rowColors[1] = color2;

Here

unsigned char *rowColors = NULL;

rowColors is a 无符号字符指针 i.e rowColors[0]是一个单一的字符和一个字符无法容纳字符缓冲区像下面这样

rowColors[0] = color1; /* rowColors[0] is a char, it can't hold char buffer color1 */
rowColors[1] = color2;

如果您想存储多个字符缓冲区，例如color1 and color2 into rowColors，它应该是unsigned char**键入或指针数组不只是unsigned char* type.

示例代码

unsigned char color1[3] = {0, 0, 0};
unsigned char color2[3] = {0, 255, 255};

unsigned char *rowColors[2]; /* USE ARRAY OF POINTERS */
for(int row = 0;row < 2; row++) {
    rowColors[row] = malloc(MAX_EACH_BUF_SIZE)); /* ALLOCATE MEMORY FOR EACH POINTER FIRST, define MAX_EACH_BUF_SIZE value accordingly */
}
/* AND THEN STORE INTO ARRAY OF POINTER */
rowColors[0] = color1;
rowColors[1] = color2;