我进行了搜索,但无法找到获取这种格式的日期的方法(DD.MM.YYYY)
请帮助我更改此请求:
DECLARE @date datetime
set @date = '01.05.2016'
SELECT [User], cast(DATEADD(SECOND, sum(datediff(DAY, @date,[Start])),@date) as date)'Date'
,cast(DATEADD(SECOND, sum(datediff(SECOND, '00:00:00',[Period])),'00:00:00') as time)'Total time'
FROM [Table].[TableAction]
where
[Start] >= @date+'00:00:00' and [Start] <= @date+'23:59:59'
group by [USER]
DECLARE @date datetime set @date = GETDATE()
现在要输出它,您需要“格式化”它。
select FORMAT (@date,'MM.dd.yy') as date
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