Python：当我使用 grep 时出现 UnicodeEncodeError

我正在使用一个简单的 python 脚本来获取我的 CID 的预订结果：simple.py:

data = {"minorRev":"current minorRev #","cid":"xxx","apiKey":"xxx","customerIpAddress":"  ","creationDateStart":"03/31/2013","}

url = 'http://someservice/services/rs/'                      
req = requests.get(url,params=data)                        
print req                                                                 
print req.text                                                                
print req.status_code

现在，如果我这样做的话，在命令提示符下python simple.py它运行完美并打印req.text多变的

但是当我尝试做时

python simple.py | grep pattern

I get

UnicodeEncodeError: 'ascii' codec can't encode character u'\xe4' in position 1314: ordinal not in range(128)

print needs在发送到 stdout 之前对字符串进行编码，但是当进程位于管道中时，sys.stdout.encoding is None, so print收到一个unicode对象，然后尝试使用以下方法对该对象进行编码ascii编解码器——如果其中包含非 ASCII 字符unicode对象，将引发异常。

你可以解决这个问题编码所有unicode物体before将其发送到标准输出（但您需要猜测要使用哪个编解码器）。请参阅这些示例：

File wrong.py:

# coding: utf-8

print u'Álvaro'

Result:

alvaro@ideas:/tmp
$ python wrong.py 
Álvaro
alvaro@ideas:/tmp
$ python wrong.py | grep a
Traceback (most recent call last):
  File "wrong.py", line 3, in <module>
    print u'Álvaro'
UnicodeEncodeError: 'ascii' codec can't encode character u'\xc1' in position 0: ordinal not in range(128)

File right.py:

# coding: utf-8

print u'Álvaro'.encode('utf-8')
# unicode object encoded == `str` in Python 2

Result:

alvaro@ideas:/tmp
$ python right.py 
Álvaro
alvaro@ideas:/tmp
$ python right.py | grep a
Álvaro