您可以使用以下方法将控件的可见性绑定到 RadioButton 的 IsChecked 属性:BooleanToVisibilityConverter
:
<Page
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
<Page.Resources>
<BooleanToVisibilityConverter x:Key="convVisibility"/>
</Page.Resources>
<Grid>
<StackPanel Orientation="Vertical">
<RadioButton Name="radioButton1" GroupName="group1">Control1</RadioButton>
<RadioButton Name="radioButton2" GroupName="group1">Control2</RadioButton>
<RadioButton Name="radioButton3" GroupName="group1">Control3</RadioButton>
<Grid>
<Button Visibility="{Binding IsChecked, ElementName=radioButton1, Converter={StaticResource convVisibility}}">1. Button</Button>
<TextBlock Visibility="{Binding IsChecked, ElementName=radioButton2, Converter={StaticResource convVisibility}}">2. TextBlock</TextBlock>
<TextBox Visibility="{Binding IsChecked, ElementName=radioButton3, Converter={StaticResource convVisibility}}">3. TextBox</TextBox>
</Grid>
</StackPanel>
</Grid>
</Page>
EDIT :
该解决方案效果很好,而且实施起来很简单。无论如何,我可以防止控件在设计模式下隐藏吗?
我不知道其他设计器(例如 Blend),但在 Visual Studio 设计器中,控件永远不会隐藏......
无论如何,您可以实现自己的转换器,它在设计模式下始终返回 Visible。由于某些不明原因,BooleanToVisibilityConverter 类是密封的,因此您无法从它继承。如果您不想重写转换逻辑,您可以将转换委托给 BooleanToVisibilityConverter :
public class MyBooleanToVisibilityConverter : IValueConverter
{
private BooleanToVisibilityConverter _converter = new BooleanToVisibilityConverter();
private DependencyObject _dummy = new DependencyObject();
private bool DesignMode
{
get
{
return DesignerProperties.GetIsInDesignMode(_dummy);
}
}
#region IValueConverter Members
public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
{
if (DesignMode)
return Visibility.Visible;
else
return _converter.Convert(value, targetType, parameter, culture);
}
public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
{
return _converter.ConvertBack(value, targetType, parameter, culture);
}
#endregion
}