我需要使用 JSON 数据制定一个 url，如下所示
http://someurl.com/passfail?parameter= http://someurl.com/passfail?parameter={“data1”：“123456789”，“data2”：“123456789”}，我需要使用 JBoss 的 ClientResponse 传递它来获取响应状态。
我首先尝试传入文字字符串数据
ClientRequest clientrequest = new ClientRequest("http://someurl.com/passfail?parameter={\"data1\":\"123456789\",\"data2\":\"123456789\"});// assuming the "\" is formulated correctly
但它给出了一个例外。
因此我也尝试使用 URL url = new URL(the url) 但它不起作用。
我在尝试时遇到了以下异常，我感觉很困难，希望有人能提供帮助。
非法参数异常：
org.jboss.resteasy.specimpl.UriBuilderImpl.buildFromMap(UriBuilderImpl.java:408)>
org.jboss.resteasy.specimpl.UriBuilderImpl.buildFromValues(UriBuilderImpl.java:558)>
org.jboss.resteasy.specimpl.UriBuilderImpl.build(UriBuilderImpl.java:539)>
org.jboss.resteasy.client.ClientRequest.getUri(ClientRequest.java:786)>
org.jboss.resteasy.client.core.executors.ApacheHttpClientExecutor.execute(ApacheHttpClientExecutor.java:77)>
org.jboss.resteasy.core.interception.ClientExecutionContextImpl.proceed(ClientExecutionContextImpl.java:39)>
org.jboss.resteasy.plugins.interceptors.encoding.AcceptEncodingGZIPInterceptor.execute(AcceptEncodingGZIPInterceptor.java:40)>
org.jboss.resteasy.core.interception.ClientExecutionContextImpl.proceed(ClientExecutionContextImpl.java:45)>
org.jboss.resteasy.client.ClientRequest.execute(ClientRequest.java:473)>
org.jboss.resteasy.client.ClientRequest.httpMethod(ClientRequest.java:704)>
org.jboss.resteasy.client.ClientRequest.get(ClientRequest.java:509)>
org.jboss.resteasy.client.ClientRequest.get(ClientRequest.java:537)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:727)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:820)>
weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227)>
weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:175)>
weblogic.servlet.internal.RequestDispatcherImpl.invokeServlet(RequestDispatcherImpl.java:505)>
weblogic.servlet.internal.RequestDispatcherImpl.forward(RequestDispatcherImpl.java:251)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet JSP
weblogic.servlet.jsp.JspBase.service(JspBase.java:34)>
weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227)>
weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:175)>
weblogic.servlet.internal.RequestDispatcherImpl.invokeServlet(RequestDispatcherImpl.java:505)>
weblogic.servlet.internal.RequestDispatcherImpl.forward(RequestDispatcherImpl.java:251)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:727)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:820)>
weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227)>
weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:175)>
weblogic.servlet.internal.RequestDispatcherImpl.invokeServlet(RequestDispatcherImpl.java:505)>
weblogic.servlet.internal.RequestDispatcherImpl.forward(RequestDispatcherImpl.java:251)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:727)>
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX at line personal Servlet
javax.servlet.http.HttpServlet.service(HttpServlet.java:820)>
weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227)>
weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292)>
weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:175)>
weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3498)>
weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)>
weblogic.security.service.SecurityManager.runAs(Unknown Source)>
weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2180)>
weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2086)>
weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1406)>
weblogic.work.ExecuteThread.execute(ExecuteThread.java:201)>
weblogic.work.ExecuteThread.run(ExecuteThread.java:173)>
Caused by: java.lang.IllegalArgumentException>
java.net.URI.create(URI.java:842)>
org.jboss.resteasy.specimpl.UriBuilderImpl.buildFromMap(UriBuilderImpl.java:404)>
... 60 more>
Caused by: java.net.URISyntaxException: Illegal character in query index 77: http://someurl.com/passfail?parameter={"data1":"123456789","data2":"123456789"}>
java.net.URI$Parser.fail(URI.java:2809)>
java.net.URI$Parser.checkChars(URI.java:2982)>
java.net.URI$Parser.parseHierarchical(URI.java:3072)>
java.net.URI$Parser.parse(URI.java:3014)>
java.net.URI.<init>(URI.java:578)>
java.net.URI.create(URI.java:840)>
... 61 more>
问题是您在 URI 字符串中传递了非法字符：Java - 将字符串转换为有效的 URI 对象 https://stackoverflow.com/questions/573184/java-convert-string-to-valid-uri-object
http://someurl.com/passfail?parameter={"data1":"123456789","data2":"123456789"}>
您需要“转义” URI 中的违规字符。
以下是一些替代方案：
我应该如何转义 JSON 中的字符串？ https://stackoverflow.com/questions/3020094/how-should-i-escape-strings-in-json
Java - 将字符串转换为有效的 URI 对象 https://stackoverflow.com/questions/573184/java-convert-string-to-valid-uri-object
如何对 URI 参数值进行编码？ https://stackoverflow.com/questions/444112/how-do-i-encode-uri-parameter-values
用Java编码URL查询参数 https://stackoverflow.com/questions/5330104/encoding-url-query-parameters-in-java
http://docs.oracle.com/javase/6/docs/api/java/net/URI.html http://docs.oracle.com/javase/6/docs/api/java/net/URI.html
最后但并非最不重要：
- java.net.URLEncoder http://docs.oracle.com/javase/6/docs/api/jav/net/URLEncoder.html
PS：你的网址中的“>”怎么样？
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