这些是我的变量：
> dput(y)
c(-22.0713165394207, 14.0880914427811, 10.9650636244176, -1.96648890706268,
-5.30593850426708, -7.54651916037787, 3.84914747321197, 4.4986386904214,
1.73067625014435, 2.5585960595839, -2.72766183793304, -3.10167452216202,
2.68853838208521, 1.12662203717498, 1.24951279248057, 3.70075666289518,
-6.11243972144607, -6.91019769671849, 6.46767794752582, 8.84874735514293,
2.95606352319898, 3.23883851668917, -2.61692776879569)
> dput(x)
c(`1` = 0.0520523266234464, `2` = Inf, `3` = 0.0520523266234462,
`4` = 0.0520523266234463, `5` = 0.0520523266234463, `6` = 0.0520523266234461,
`7` = 0.0520523266234463, `8` = 0.0520523266234466, `9` = 0.0520523266234465,
`10` = 0.0520523266234465, `11` = 0.0520523266234465, `12` = 0.0520523266234466,
`13` = 0.0520523266234468, `14` = 0.0520523266234466, `15` = 0.0520523266234467,
`16` = 0.0520523266234464, `17` = 0.0520523266234463, `18` = 0.0520523266234465,
`19` = 0.0520523266234466, `20` = 0.0520523266234463, `21` = 0.0520523266234464,
`22` = 0.0520523266234465, `23` = 0.0520523266234464)
当我运行回归时：summary(lm(ex.return ~ ex.return.skew))
我有这个错误消息：
Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) :
NA/NaN/Inf in 'x'
我尝试删除位置 2，然后运行回归，但我无法执行此操作，因为数据要大得多。因此，我正在寻找一种忽略 Inf/Na 值并运行回归的方法。
我怎样才能做到这一点？
有什么帮助吗？
