Django：如何允许可疑文件操作/复制文件

我想做一个SuspiciousFileOperationdjango 默认是不允许的。

我正在编写一个命令（通过运行manage.py importfiles）在我自己编写的 Django 文件存储中导入真实文件系统上给定的目录结构。

我想，这是我的相关代码：

def _handle_directory(self, directory_path, directory):
    for root, subFolders, files in os.walk(directory_path):
        for filename in files:
            self.cnt_files += 1
            new_file = File(directory=directory, filename=filename, file=os.path.join(root, filename),
                 uploader=self.uploader)
            new_file.save()

回溯是：

Traceback (most recent call last):
  File ".\manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "C:\Python27\lib\site-packages\django\core\management\__init__.py", line 399, in execute_from_command_line
    utility.execute()
  File "C:\Python27\lib\site-packages\django\core\management\__init__.py", line 392, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "C:\Python27\lib\site-packages\django\core\management\base.py", line 242, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "C:\Python27\lib\site-packages\django\core\management\base.py", line 285, in execute
    output = self.handle(*args, **options)
  File "D:\Development\github\Palco\engine\filestorage\management\commands\importfiles.py", line 53, in handle
    self._handle_directory(args[0], root)
  File "D:\Development\github\Palco\engine\filestorage\management\commands\importfiles.py", line 63, in _handle_directory
    new_file.save()
  File "D:\Development\github\Palco\engine\filestorage\models.py", line 157, in save
    self.sha512 = hashlib.sha512(self.file.read()).hexdigest()
  File "C:\Python27\lib\site-packages\django\core\files\utils.py", line 16, in <lambda>
    read = property(lambda self: self.file.read)
  File "C:\Python27\lib\site-packages\django\db\models\fields\files.py", line 46, in _get_file
    self._file = self.storage.open(self.name, 'rb')
  File "C:\Python27\lib\site-packages\django\core\files\storage.py", line 33, in open
    return self._open(name, mode)
  File "C:\Python27\lib\site-packages\django\core\files\storage.py", line 160, in _open
    return File(open(self.path(name), mode))
  File "C:\Python27\lib\site-packages\django\core\files\storage.py", line 261, in path
    raise SuspiciousFileOperation("Attempted access to '%s' denied." % name)
django.core.exceptions.SuspiciousFileOperation: Attempted access to 'D:\Temp\importme\readme.html' denied.

The 完整模型可以在 GitHub 上找到 https://github.com/omeinusch/Palco/blob/master/engine/filestorage/models.py. The 完整的命令目前在 gist.github.com 上可用 https://gist.github.com/omeinusch/0c40f9a0e35f2e58adca/d1d2fd506c52065a24f3dfafa27410e1c24a5b11.

如果您不想检查模型：属性file of my File类是一个文件字段 https://docs.djangoproject.com/en/dev/ref/models/fields/#django.db.models.FileField.

我认为，这个问题发生了，因为我只是“链接”到找到的文件。但我需要复制它，对吧？如何将文件复制到文件中？

在 Django 中，可以通过从外部目录读取文件并在项目媒体中创建一个 tmp 文件然后保存在适当的文件中来避免可疑文件操作，如下所示

import tempfile

file_name="file_name.pdf"
EXT_FILE_PATH = "/home/somepath/"
file_path = EXT_FILE_PATH + file_name
if exists(file_path):
    #create a named temporary file within the project base , here in media

    lf = tempfile.NamedTemporaryFile(dir='media')
    f = open(file_path, 'rb')
    lf.write(f.read())
    #doc object with file FileField.

    doc.file.save(file_name, File(lf), save=True)
    lf.close()