下面的代码抛出一个java.lang.IllegalMonitorStateException当我关闭播放服务器时出现异常;它是由a.等待(1000)调用onStop方法。谁能告诉我为什么会出现这种情况以及如何优雅地等待 Actor 在 Play 框架关闭内完成?
import play.api.GlobalSettings
import play.api.libs.concurrent.Akka
import akka.actor.{ Actor, Props }
import play.api.libs.concurrent.Execution.Implicits.defaultContext
import play.api.Play.current
import models.{ TestActor, StartMessage, StopMessage }
object Global extends GlobalSettings {
override def onStart(application : play.api.Application) {
val a = Akka.system.actorOf(Props[TestActor], name = "test-actor")
a ! StartMessage("Start instruction")
}
override def onStop(application : play.api.Application) {
val a = Akka.system.actorSelection("akka://application/user/test-actor")
a ! StopMessage("Stop instruction")
a.wait(1000)
Akka.system.shutdown()
}
}
Update:
这是完整的解决方案,采用以下答案:
import play.api.GlobalSettings
import play.api.libs.concurrent.Akka
import akka.actor.{ Actor, Props }
import play.api.libs.concurrent.Execution.Implicits.defaultContext
import play.api.Play.current
import models.{ TestActor, StartMessage, StopMessage }
import akka.pattern.gracefulStop
import scala.concurrent.Future
import scala.concurrent.duration.FiniteDuration
import scala.concurrent.Await
import com.typesafe.config.impl.ResolveContext
import com.typesafe.config.impl.ResolveContext
import akka.actor.ActorIdentity
object Global extends GlobalSettings {
override def onStart(application : play.api.Application) {
val a = Akka.system.actorOf(Props[TestActor], name = "test-actor")
a ! StartMessage("Start Instruction")
}
override def onStop(application : play.api.Application) {
val a = Akka.system.actorFor("akka://application/user/test-actor")
a ! StopMessage("Stop Instruction")
try {
val stopped : Future[Boolean] = gracefulStop(a, scala.concurrent.duration.Duration(5, "seconds"))
Await.result(stopped, scala.concurrent.duration.Duration(6, "seconds"))
// the actor has been stopped
}
catch {
case e : akka.pattern.AskTimeoutException => // the actor wasn't stopped within 5 seconds
}
Akka.system.shutdown()
Akka.system.awaitTermination()
}
}
“优雅的停下来
如果您需要等待终止或组合多个参与者的有序终止,gracefulStop 非常有用:
import akka.pattern.gracefulStop
import akka.dispatch.Await
import akka.actor.ActorTimeoutException
try {
val stopped: Future[Boolean] = gracefulStop(actorRef, 5 seconds)(system)
Await.result(stopped, 6 seconds)
// the actor has been stopped
} catch {
case e: ActorTimeoutException ⇒ // the actor wasn't stopped within 5 seconds
}
"
- http://doc.akka.io/docs/akka/2.0/scala/actors.html#Graceful_Stop http://doc.akka.io/docs/akka/2.0/scala/actors.html#Graceful_Stop
附言。谷歌搜索“优雅的演员阿卡”给出的答案是最重要的结果。
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)