骨干木偶区域显示无渲染

是否可以将已渲染的视图放入骨干牵线木偶区域而无需再次渲染？

例如：

region.show(myView); // This will call render on myView

我不希望该区域再次呈现我的视图。

If I do:

region.attachView(myView); // This won't render myView, but it also won't show it

首先重写 marionette ItemView 构造函数并像这样渲染（如果您想在 CollectionView 和 CompositeView 中使用它，也重写它们的这些方法）：

var fnCons = Marionette.ItemView.prototype.constructor,
    fnRender = Marionette.ItemView.prototype.render;
Marionette.ItemView.prototype.constructor = function(){
  this.firstRender = true;
  fnCons.apply(this,arguments);       
}

Marionette.ItemView.prototype.render = function(){
  this.firstRender = false;
  fnRender.apply(this,arguments);
}

然后只需覆盖默认区域#show，如果视图是view.firstRender为 true 时，它​​尚未渲染并且必须渲染它，否则无需执行任何操作。

Marionette.Region.prototype.show = function(view){    
  this.ensureEl();

  var isViewClosed = view.isClosed || _.isUndefined(view.$el);

  var isDifferentView = view !== this.currentView;

  if (isDifferentView) {
    this.close();
  }
  // These lines changed from default marionette action
  if(view.firstRender){
    view.render();
  }else{
    // Don anything else!
  }
  // End of overrided code


  if (isDifferentView || isViewClosed) {
    this.open(view);
  }

  this.currentView = view;

  Marionette.triggerMethod.call(this, "show", view);
  Marionette.triggerMethod.call(view, "show");
}

Edit

上面的解决方案工作正常，另一种方法是（这将假设视图已渲染）：

Marionette.Region.prototype.showWithoutRender = function(view){
  this.ensureEl();

  var isViewClosed = view.isClosed || _.isUndefined(view.$el);
  var isDifferentView = view !== this.currentView;

  if (view !== this.currentView) {
    this.close();
  }

  if(isViewClosed || isDifferentView){
    this.open(view);
  }
  this.currentView = view;

  Marionette.triggerMethod.call(this, "show", view);
  Marionette.triggerMethod.call(view, "show");
}