PyAudio 输入溢出

我正在尝试用 python 发出实时绘图声音。我需要从我的麦克风中获取数据块。

使用 PyAudio，尝试使用

import pyaudio
import wave
import sys

chunk = 1024
FORMAT = pyaudio.paInt16
CHANNELS = 1
RATE = 44100
RECORD_SECONDS = 5
WAVE_OUTPUT_FILENAME = "output.wav"

p = pyaudio.PyAudio()

stream = p.open(format = FORMAT,
                channels = CHANNELS,
                rate = RATE,
                input = True,
                frames_per_buffer = chunk)

print "* recording"
all = []
for i in range(0, RATE / chunk * RECORD_SECONDS):
    data = stream.read(chunk)
    all.append(data)
print "* done recording"

stream.close()
p.terminate()

之后，我收到以下错误：

* recording
Traceback (most recent call last):
  File "gg.py", line 23, in <module>
    data = stream.read(chunk)
  File "/usr/lib64/python2.7/site-packages/pyaudio.py", line 564, in read
    return pa.read_stream(self._stream, num_frames)
IOError: [Errno Input overflowed] -9981

我无法理解这个缓冲区。我想使用阻塞 IO 模式，所以如果块不可用，我想等待这些块。但是当我创建尝试除了段或睡眠（0.1）时，我听到点击声，所以这不是我想要的。

请针对我的问题提出最佳解决方案？

pyaudio.Stream.read()有一个关键字参数exception_on_overflow，将其设置为 False。

对于您的示例代码，如下所示：

import pyaudio
import wave
import sys

chunk = 1024
FORMAT = pyaudio.paInt16
CHANNELS = 1
RATE = 44100
RECORD_SECONDS = 5
WAVE_OUTPUT_FILENAME = "output.wav"

p = pyaudio.PyAudio()

stream = p.open(format = FORMAT,
                channels = CHANNELS,
                rate = RATE,
                input = True,
                frames_per_buffer = chunk)

print "* recording"
all = []
for i in range(0, RATE / chunk * RECORD_SECONDS):
    data = stream.read(chunk, exception_on_overflow = False)
    all.append(data)
print "* done recording"

stream.close()
p.terminate()

See the PyAudio 文档 https://people.csail.mit.edu/hubert/pyaudio/docs/#pyaudio.Stream.read更多细节。