我想在鼠标悬停时显示一个信息框JTable细胞使用Java 摇摆，所以有多个部分
- 如何捕获表格单元格中的鼠标悬停事件？我必须能够设置单元格内容，然后获取其数据。
- 如何将鼠标悬停在该单元格上时显示带有动态服务器数据的面板/框？
- 如何缓存信息面板/框，这样我就不必在每次鼠标悬停时查询服务器？
Example:
在表格单元格中，我输入：94903。按 Tab 键或输入后，单元格将设置为数字。鼠标悬停时，会显示一个包含姓名、地址、电话号码、电子邮件等的框。
Thanks!
您可以使用 HTML 格式化工具提示文本，这将允许您向工具提示提供复杂的信息结构，而无需或花费编写自己的解决方案。唯一的问题是工具提示将被自动丢弃。
如果这仍然不适合，您可以尝试：
import java.awt.Point;
import java.awt.Rectangle;
import java.awt.event.*;
import javax.swing.JPopupMenu;
import javax.swing.JTable;
import javax.swing.Timer;
public class TestTable {
private Timer showTimer;
private Timer disposeTimer;
private JTable table;
private Point hintCell;
private MyPopup popup; // Inherites from JPopupMenu
public TestTable() {
showTimer = new Timer(1500, new ShowPopupActionHandler());
showTimer.setRepeats(false);
showTimer.setCoalesce(true);
disposeTimer = new Timer(5000, new DisposePopupActionHandler());
disposeTimer.setRepeats(false);
disposeTimer.setCoalesce(true);
table.addMouseMotionListener(new MouseMotionAdapter() {
@Override
public void mouseMoved(MouseEvent e) {
Point p = e.getPoint();
int row = table.rowAtPoint(p);
int col = table.columnAtPoint(p);
if ((row > -1 && row < table.getRowCount()) && (col > -1 && col < table.getColumnCount())) {
if (hintCell == null || (hintCell.x != col || hintCell.y != row)) {
hintCell = new Point(col, row);
Object value = table.getValueAt(row, col);
// Depending on how the data is stored, you may need to load more data
// here...
// You will probably want to maintain a reference to the object hint data
showTimer.restart();
}
}
}
});
}
protected MyPopup getHintPopup() {
if (popup == null) {
// Construct the popup...
}
return popup;
}
public class ShowPopupActionHandler implements ActionListener {
@Override
public void actionPerformed(ActionEvent e) {
if (hintCell != null) {
disposeTimer.stop(); // don't want it going off while we're setting up
MyPopup popup = getHintPopup();
popup.setVisible(false);
// You might want to check that the object hint data is update and valid...
Rectangle bounds = table.getCellRect(hintCell.y, hintCell.x, true);
int x = bounds.x;
int y = bounds.y + bounds.height;
popup.show(table, x, y);
disposeTimer.start();
}
}
}
public class DisposePopupActionHandler implements ActionListener {
@Override
public void actionPerformed(ActionEvent e) {
MyPopup popup = getHintPopup();
popup.setVisible(false);
}
}
}
现在，我还没有构建弹出窗口，我也会使用 Bob Sinclar 的答案中的弹出菜单
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