我有一个像这样的xml:
<todo>
<doLaundry cost="1"/>
<washCar cost="10"/>
<tidyBedroom cost="0" experiencePoints="5000"/>
</todo>
它的 XSD 架构是:
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:complexType name="todo">
<xs:sequence>
<xs:choice maxOccurs="unbounded">
<xs:element name="doLaundry" type="doLaundry" />
<xs:element name="washCar" type="washCar" />
<xs:element name="tidyBedroom" type="tidyBedroom" />
</xs:choice>
</xs:sequence>
</xs:complexType>
<xs:complexType name="doLaundry">
<xs:attribute name="cost" type="xs:int" />
</xs:complexType>
<xs:complexType name="washCar">
<xs:attribute name="cost" type="xs:int" />
</xs:complexType>
<xs:complexType name="tidyBedroom">
<xs:attribute name="cost" type="xs:int" />
<xs:attribute name="experiencePoints" type="xs:int" />
</xs:complexType>
</xs:schema>
当我通过 JAXB 处理这个模式时,我得到一个具有如下方法的类:
public class Todo {
public List<Object> getDoLaundryOrWashCarOrTidyBedroom() {
...
}
}
理想情况下,我想要的是一种定义所有其他 XSD 类型扩展的通用基本类型的方法。从 XSD 模式生成的 Jaxb 类应该有一个方法来返回通用任务列表。这将使向待办事项列表添加新任务变得非常容易:
public class Todo {
public List<Task> getTasks() {
...
}
}
public abstract class Task {
public int getCost() {
...
}
}
public class TidyBedroom extends Task {
public int getExperiencePoints() {
...
}
}
为了生成上述 Java 类,XSD 模式应该是什么样子?
我在 Blaise Doughan 的文章的帮助下找到了答案:http://bdoughan.blogspot.com/2010/11/jaxb-and-inheritance-using-xsitype.html http://bdoughan.blogspot.com/2010/11/jaxb-and-inheritance-using-xsitype.html
这个架构:
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:complexType name="todo">
<xs:sequence>
<xs:choice maxOccurs="unbounded">
<xs:element name="doLaundry" type="doLaundry" />
<xs:element name="washCar" type="washCar" />
<xs:element name="tidyBedroom" type="tidyBedroom" />
</xs:choice>
</xs:sequence>
</xs:complexType>
<xs:complexType abstract="true" name="Task">
<xs:attribute name="cost" type="xs:int" use="required" />
</xs:complexType>
<xs:complexType name="doLaundry">
<xs:complexContent>
<xs:extension base="Task">
</xs:extension>
</xs:complexContent>
</xs:complexType>
<xs:complexType name="washCar">
<xs:complexContent>
<xs:extension base="Task">
</xs:extension>
</xs:complexContent>
</xs:complexType>
<xs:complexType name="tidyBedroom">
<xs:complexContent>
<xs:extension base="Task">
<xs:attribute name="experiencePoints" type="xs:int" />
</xs:extension>
</xs:complexContent>
</xs:complexType>
</xs:schema>
与绑定文件结合:
<jxb:bindings version="1.0" xmlns:jxb="http://java.sun.com/xml/ns/jaxb" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<jxb:bindings>
<jxb:bindings schemaLocation="todo.xsd" node="/xs:schema/xs:complexType[@name='todo']/xs:sequence/xs:choice">
<jxb:property name="Tasks"/>
</jxb:bindings>
</jxb:bindings>
</jxb:bindings>
将给出我在问题中描述的抽象类和继承类。绑定文件会将 Jaxb 的默认方法名称从 getDoLaundryOrWashCarOrTidyBedroom() 更改为 getTasks()。
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