我想保留原始请求的原始有效负载，并将其放入 xslt-transformer 或其他操作中。我丢失了它，因为我使用 xslt-transformer 并且我只需要转换中的一些元素。所以我的场景是：
1.inbound-gateway（传入 WS 请求）-> 2.xslt-transformer（用于调用外部 WS 的映射）-> 3.outbound-gateway（调用外部 WS）-> 4.xslt-transformer（从分别是外部 WS 和原始请求）
在第四步，我没有原始的请求，但我需要它，因为我必须将其中的值放入响应中。我怎样才能实现它？
谢谢，
五、
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:int="http://www.springframework.org/schema/integration" xmlns:int-ws="http://www.springframework.org/schema/integration/ws" xmlns:int-xml="http://www.springframework.org/schema/integration/xml" xmlns:util="http://www.springframework.org/schema/util" xsi:schemaLocation="http://www.springframework.org/schema/integration/ws http://www.springframework.org/schema/integration/ws/spring-integration-ws.xsd http://www.springframework.org/schema/integration http://www.springframework.org/schema/integration/spring-integration.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/integration/xml http://www.springframework.org/schema/integration/xml/spring-integration-xml.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd">
<bean id="authenticator" class="uk.co.virginmedia.test.Authenticator"/>
<bean id="webserviceDestinationProvider" class="uk.co.virginmedia.test.WebserviceDestinationProvider"/>
<bean id="resultToDocumentTransformer" class="org.springframework.integration.xml.transformer.ResultToDocumentTransformer"/>
<util:map id="orderNamespaceMap">
<entry key="res" value="http://schema/ReserveAppointment/2/0" />
</util:map>
<int-ws:inbound-gateway id="ws-gateway-for-rbta" request-channel="incoming-req-channel" reply-channel=""/>
<int:channel id="incoming-req-channel"/>
<int:service-activator id="authentication" input-channel="incoming-req-channel" ref="authenticator" method="authenticate" output-channel="authenticated-channel" />
<int:channel id="authenticated-channel"/>
<int-xml:xpath-router id="servicetype-router" input-channel="authenticated-channel" evaluate-as-string="true">
<int-xml:xpath-expression expression="//res:ReserveAppointmentRequest/res:serviceType/text()" ns-prefix="res" ns-uri="http://schema/ReserveAppointment/2/0"/>
<int-xml:mapping value="Broadband" channel="broadband-channel"/>
<int-xml:mapping value="FTTC+WholesaleLineRental" channel="fttc-wlr-channel"/>
</int-xml:xpath-router>
<int:channel id="broadband-channel"/>
<int-xml:xslt-transformer id="req_for_bt_xslt_transformer" input-channel="broadband-channel" output-channel="domresult_for_bt_channel" xsl-resource="classpath:/xsl/ToBTReq.xsl" result-type="StringResult"/>
<int:channel id="domresult_for_bt_channel"/>
<int:transformer input-channel="domresult_for_bt_channel" output-channel="document_for_bt_channel" expression="payload.toString()"/>
<int:channel id="document_for_bt_channel"/>
<int-ws:outbound-gateway request-channel="document_for_bt_channel" reply-channel="resp_from_bt_channel" destination-provider="webserviceDestinationProvider" id="call_bt-outbound_gateway" />
<int:channel id="resp_from_bt_channel"/>
<int-xml:xslt-transformer id="resp_for_rbta_xslt_transformer" input-channel="resp_from_bt_channel" output-channel="resp_for_rbta_channel" xsl-resource="classpath:/xsl/ToBTReq.xsl" result-type="StringResult"/>
由于您的原始消息只是文本，您可以将其复制到标题字段。只要您在存储和检索它之间不执行任何特殊操作，这应该就可以工作。
所以我想尝试的是：
<int:header-enricher input-channel="authenticated-channel" output-channel="pre-routing-channel">
<int:header name="original-payload" expression="payload.toString()" />
</int:header-enricher>
<!-- changed input channel of router -->
<int-xml:xpath-router id="servicetype-router" input-channel="pre-routing-channel" evaluate-as-string="true">
如果这对您不起作用（可能是因为您必须在中间做一些更特殊的事情或者有效负载太大），您仍然可以选择使用索赔检查 http://static.springsource.org/spring-integration/docs/2.2.x/reference/html/messaging-transformation-chapter.html#claim-check。这实际上正是您所要求的。为此你需要一个消息库 http://static.springsource.org/spring-integration/docs/2.2.x/reference/html/system-management-chapter.html#message-store然后在修改之前存储消息有效负载。因此，您将调用而不是标头丰富器
<int:claim-check-in input-channel="authenticated-channel" output-channel="pre-routing-channel" message-store="payloadstore" />
<!-- MessageStore definition storing payload using in memory map -->
<bean id="simpleMessageStore"
class="org.springframework.integration.store.SimpleMessageStore"/>
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