你能在 MS Windows 上用 Python 将 stdin 作为文件打开吗？

在 Linux 上，我使用 subbprocess.Popen 来运行应用程序。该应用程序的命令行需要输入文件的路径。我了解到我可以将路径 /dev/stdin 传递到命令行，然后使用 Python 的 subproc.stdin.write() 将输入发送到子进程。

import subprocess
kw['shell'] = False
kw['executable'] = '/path/to/myapp'
kw['stdin'] = subprocess.PIPE
kw['stdout'] = subprocess.PIPE
kw['stderr'] = subprocess.PIPE
subproc = subprocess.Popen(['','-i','/dev/stdin'],**kw)
inbuff = [u'my lines',u'of text',u'to process',u'go here']
outbuff = []
conditionbuff = []

def processdata(inbuff,outbuff,conditionbuff):
    for i,line in enumerate(inbuff):
        subproc.stdin.write('%s\n'%(line.encode('utf-8').strip()))
        line = subproc.stdout.readline().strip().decode('utf-8')
        if 'condition' in line:
            conditionbuff.append(line)
        else:
            outbuff.append(line)

processdata(inbuff,outbuff,conditionbuff)

该应用程序还有 MS Windows 版本。 MS Windows 上是否有与使用 /dev/stdin 等效的方法，或者是 Linux (Posix) 特定的解决方案？

If myapp treats -作为表示 stdin 的特殊文件名：

from subprocess import PIPE, Popen

p = Popen(['/path/to/myapp', '-i', '-'], stdin=PIPE, stdout=PIPE)
stdout, _ = p.communicate('\n'.join(inbuff).encode('utf-8'))
outbuff = stdout.decode('utf-8').splitlines()

如果你无法通过-那么你可以使用临时文件：

import os
import tempfile

with tempfile.NamedTemporaryFile(delete=False) as f:
     f.write('\n'.join(inbuff).encode('utf-8'))

p = Popen(['/path/to/myapp', '-i', f.name], stdout=PIPE)
outbuff, conditionbuff = [], []
for line in iter(p.stdout.readline, ''):
    line = line.strip().decode('utf-8')
    if 'condition' in line:
        conditionbuff.append(line)
    else:
        outbuff.append(line)
p.stdout.close()
p.wait()
os.remove(f.name) #XXX add try/finally for proper cleanup

压制stderr你可以通过open(os.devnull, 'wb') as stderr to Popen.