string_agg 没有函数与给定名称匹配

我有关系数据库并想使用string_agg()因为它似乎适合我的需要。

I want :

product_id | quiz_id
-----------+----------
         1 | 1,6
         2 | 2,7
         3 | 3,8
         4 | 4

这是我的数据库。

    select quiz_id , product_id, lastmodified from dugong.quiz;
 quiz_id | product_id |         lastmodified          
---------+------------+-------------------------------
       1 |          1 | 2015-11-11 14:46:55.619162+07
       2 |          2 | 2015-11-11 14:46:55.619162+07
       3 |          3 | 2015-11-11 14:46:55.619162+07
       4 |          4 | 2015-11-11 14:46:55.619162+07
       5 |          5 | 2015-11-11 14:46:55.619162+07
       6 |          1 | 2015-11-11 14:46:55.619162+07
       7 |          2 | 2015-11-11 14:46:55.619162+07
       8 |          3 | 2015-11-11 14:46:55.619162+07

我的尝试：
参见文档。如何在 PostgreSQL“group by”查询中连接字符串字段的字符串？ https://stackoverflow.com/questions/43870/how-to-concatenate-strings-of-a-string-field-in-a-postgresql-group-by-query http://www.postgresql.org/docs/current/static/sql-expressions.html#SYNTAX-AGGREGATES http://www.postgresql.org/docs/current/static/sql-expressions.html#SYNTAX-AGGREGATES

select product_id , string_agg(quiz_id, ',' order by lastmodified) from dugong.quiz;
ERROR:  function string_agg(integer, unknown) does not exist
LINE 1: select product_id , string_agg(quiz_id, ',' order by lastmod...
                            ^
HINT:  No function matches the given name and argument types. You might need to add explicit type casts.

Postgres 版本：
PostgresApp 9.4.4.1

Update :
@codemonk 还是报错。

select product_id , string_agg(quiz_id::int, ',' order by lastmodified) from dugong.quiz;
ERROR:  function string_agg(integer, unknown) does not exist
LINE 1: select product_id , string_agg(quiz_id::int, ',' order by la...
                            ^
HINT:  No function matches the given name and argument types. You might need to add explicit type casts.

问题 ：
我的查询有什么问题？

尝试这个：

select product_id , string_agg(quiz_id::character varying, ',' order by lastmodified) 
from quiz group by product_id;

String_agg函数仅适用于字符串值，您收到错误是因为quiz_id是整数。

我已将其转换为character varying并添加了 group by 用于对数据产品 ID 进行分组。

SQL 小提琴示例：http://sqlfiddle.com/#!15/9dafe/1 http://sqlfiddle.com/#!15/9dafe/1