自从一年前提出这个问题以来,这可能已添加到传单包中,但这可以通过label
争论。我正在使用传单 R 包版本 1.1.0。
读取上面的数据:
library(sp)
library(leaflet)
library(dplyr)
circleFun <- function(center = c(0,0),diameter = 1, npoints = 100){
r = diameter / 2
tt <- seq(0,2*pi,length.out = npoints)
xx <- center[1] + r * cos(tt)
yy <- center[2] + r * sin(tt)
Sr1 = Polygon(cbind(xx, yy))
Srs1 = Polygons(list(Sr1), "s1")
SpP = SpatialPolygons(list(Srs1), 1:1)
return(SpP)
}
Circle.Town <- circleFun(c(1,-1),2.3,npoints = 100)
df1 <- data.frame(long=c(0.6,1,1.4), lat=c(-2, -.8, -0.2), other=c('a', 'b', 'c'), VAM=c(10,8,6),
type=c('Public', 'Public', 'Private'), id=c(1:3)) %>%
mutate(X=paste0('<strong>id: </strong>',
id,
'<br><strong>type</strong>: ',
type,
'<br><strong>VAM</strong>: ',
VAM))
# Create a continuous palette function
pal <- colorNumeric(
palette = "RdYlBu",
domain = df1$VAM
)
但创建一个标签列表而不是向量:
labs <- as.list(df1$X)
进而lapply
the HTML
函数内的该列表label
争论。使用注意事项label
代替popup
.
library(htmltools)
leaflet(height = "400px") %>%
addTiles() %>%
addPolygons(data = Circle.Town, color = 'green', fillOpacity = .7) %>%
addCircleMarkers(data = df1, lat = ~lat, lng =~long,
radius = ~VAM, label = lapply(labs, HTML),
fillColor = ~pal(VAM),
stroke = FALSE, fillOpacity = 0.8,
clusterOptions = markerClusterOptions()) %>%
addLegend(position = "topright",
pal = pal, values = df1$VAM,
title = "VAM",
opacity = 1
) %>%
setView(lng = 1, lat = -1, zoom = 8)
此方法在对此问题的回答中进行了描述:R 和 Leaflet:如何跨多行排列标签文本 https://stackoverflow.com/questions/43144596/r-and-leaflet-how-to-arrange-label-text-across-multiple-lines
传单文档中的标签中包含有关 HTML 的更多信息:https://rstudio.github.io/leaflet/popups.html https://rstudio.github.io/leaflet/popups.html