如何将 NSString 转换为 NSArray [重复]

我有一个像这样的字符串

NSString* str = @"[90, 5, 6]";

我需要将其转换为数组，例如

NSArray * numbers = [90, 5 , 6];

我做了很长一段路是这样的：

+ (NSArray*) stringToArray:(NSString*)str
{
    NSString *sep = @"[,";
    NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
    NSArray *temp=[str componentsSeparatedByCharactersInSet:set];

    NSMutableArray* numbers = [[NSMutableArray alloc] init];
    for (NSString* s in temp) {
        NSNumber *n = [NSNumber numberWithInteger:[s integerValue]];
        [numbers addObject:n];
    }

    return numbers;
}

  

有没有什么简洁快速的方法来进行这种转换？

Thanks

首先从字符串中删除不需要的字符，例如空格和大括号：

NSString* str = @"[90, 5, 6]";
NSCharacterSet* characterSet = [[NSCharacterSet
                                 characterSetWithCharactersInString:@"0123456789,"] invertedSet];
NSString* newString = [[str componentsSeparatedByCharactersInSet:characterSet]
                       componentsJoinedByString:@""];

你将得到一个像这样的字符串：90,5,6。然后简单地使用逗号分割并转换为NSNumber:

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSMutableArray* arrayOfNumbers = [NSMutableArray arrayWithCapacity:arrayOfStrings.count];
for (NSString* string in arrayOfStrings) {
    [arrayOfNumbers addObject:[NSDecimalNumber decimalNumberWithString:string]];
}

使用NSString类别来自这个回应 https://stackoverflow.com/a/3430555/469218它可以简化为：

NSArray* arrayOfStrings = [newString componentsSeparatedByString:@","];
NSArray* arrayOfNumbers = [arrayOfStrings valueForKey: @"decimalNumberValue"];