JS：按每个类别的最大值过滤对象数组

什么是最有效/优雅的方式来实现类似sql的过滤效果。我想过滤它们并只获取某个组中最大值的对象。

这是我的代码，它可以工作，但可能不是最好的方法：

uniqueValues = (arr) => [...new Set(arr)];
getMaxTimeOf = (arr) => Math.max(...arr.map(o => o.timeStamp), 0);
selectorName = (name) => (obj) => obj.name === name;
selectorTime = (time) => (obj) => obj.timeStamp === time;
getGroup = (obj, selector) => obj.filter(selector)

onlyLastChangedFrom = (history) => {
const uniqueNames = uniqueValues(history.map(o => o.name))
let filtered = []
 uniqueNames.forEach(name => {
  const group = getGroup(history, selectorName(name))
  const groupLastTime = getMaxTimeOf(group)
  const lastChange = getGroup(group, selectorTime(groupLastTime))
  filtered.push(lastChange[0])
 });
 return filtered
}   
onlyLastChangedFrom(history)

    // Input:
    [ { name: 'bathroom',
        value: 54,
        timeStamp: 1562318089713 },
      { name: 'bathroom',
        value: 55,
        timeStamp: 1562318090807 },
      { name: 'bedroom',
        value: 48,
        timeStamp: 1562318092084 },
      { name: 'bedroom',
        value: 49,
        timeStamp: 1562318092223 },
      { name: 'room',
        value: 41,
        timeStamp: 1562318093467 } ]

    // Output:
    [ { name: 'bathroom',
        value: 55,
        timeStamp: 1562318090807 },
      { name: 'bedroom',
        value: 49,
        timeStamp: 1562318092223 },
      { name: 'room',
        value: 41,
        timeStamp: 1562318093467 } ]

Reduce https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce将数组转换为对象，使用name财产为钥匙。对于每个项目，检查累加器中存在的项目是否具有比当前项目更高的值，如果没有，则将其替换为当前项目。转换回数组Object.values() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_objects/Object/values:

const arr = [{"name":"bathroom","value":54,"timeStamp":1562318089713},{"name":"bathroom","value":55,"timeStamp":1562318090807},{"name":"bedroom","value":48,"timeStamp":1562318092084},{"name":"bedroom","value":49,"timeStamp":1562318092223},{"name":"room","value":41,"timeStamp":1562318093467}]

const result = Object.values(arr.reduce((r, o) => {
  r[o.name] = (r[o.name] && r[o.name].value > o.value) ? r[o.name] : o

  return r
}, {}))

console.log(result)