我正在尝试使用以下代码在数据库中插入一些数据:
-(void)insertLocationOnDatabase:(LocationType *)aLocation {
sqlite3_stmt *stmt;
int location = [aLocation.locationID intValue];
NSLog(@"Location ID: %i", location);
const char *sql = "insert into tbl_location values (?,?,?,?)";
if (sqlite3_prepare_v2(database, sql, -1, &stmt, NULL) == SQLITE_OK) {
sqlite3_bind_int(stmt, 0, location);
sqlite3_bind_text(stmt, 1, [aLocation.Description UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(stmt, 2, [aLocation.isActive UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(stmt, 3, [aLocation.sequenceOrder UTF8String], -1, SQLITE_TRANSIENT);
if (sqlite3_step(stmt) == SQLITE_DONE) {
NSLog(@"Location %@ inserted on database",aLocation.Description);
}
else {
NSLog(@"Error on step: %i",sqlite3_errcode(database));
}
}
else {
NSLog(@"Error on prepare: %i",sqlite3_errcode(database));
}
}
问题出在网上:
sqlite3_bind_int(stmt, 0, location);
如果没有这一行并更改 sql,代码可以正常工作,但是当我放回这一行时,我收到此错误:
2010-09-17 10:24:01.032 StockControl[944:207] Error on step: 20
来自 sqlite3.h:
#define SQLITE_MISMATCH 20 /* Data type mismatch */
有人知道我的错误在哪里吗?
问候,
克劳迪奥