TSQL如何在xml列中选择具有技能的员工

在如下所示的表架构中

CREATE TABLE [dbo].[Employee](
    [EmployeeId] [uniqueidentifier] NOT NULL,
    [Name] [nvarchar](50) NOT NULL,
    [Location] [nvarchar](50) NOT NULL,
    [Skills] [xml] NOT NULL
 CONSTRAINT [PK_Employee] PRIMARY KEY CLUSTERED 

• 我如何让员工拥有C#（不区分大小写）编程技巧假设xml保存在Skills列如下。

• 您可以...吗对其他功能的建议会帮助我在使用 xml 数据类型列时进行过滤、排序

<Skills><Skill>C#</Skill><Skill>ASP.NET</Skill><Skill>VB.NET</Skill></Skills>

比较区分大小写，因此您需要与 c# 和 C# 进行比较。在 SQL Server 2008 中您可以使用大写 http://msdn.microsoft.com/en-us/library/cc645590.aspx.

declare @T table
(
  ID int identity,
  Skills XML
)

insert into @T values
('<Skills><Skill>C#</Skill><Skill>ASP.NET</Skill><Skill>VB.NET</Skill></Skills>')
insert into @T values
('<Skills><Skill>CB.NET</Skill><Skill>ASP.NET</Skill><Skill>c#</Skill></Skills>')
insert into @T values
('<Skills><Skill>F#</Skill><Skill>ASP.NET</Skill><Skill>VB.NET</Skill></Skills>')

select ID
from @T
where Skills.exist('/Skills/Skill[contains(., "C#") or contains(., "c#")]') = 1

Result:

ID
-----------
1
2

Update:

这也会起作用。

select T.ID
from @T as T
  cross apply T.Skills.nodes('/Skills/Skill') as X(N)
where X.N.value('.', 'nvarchar(50)') like '%C#%'