Python脚本递归重命名文件夹和子文件夹中的所有文件

您好，我有许多不同的文件需要重命名为其他文件。我已经走到这一步了，但我想要拥有它，这样我就可以有许多要替换的项目及其相应的替换项，而不是逐一输入，运行代码然后再次重新输入。

更新* 另外，我需要重命名以仅更改文件的一部分而不是整个文件，因此如果存在“Cat5e_1mBend1bottom50m2mBend2top-Aqeoiu31”，则只需将其更改为“'Cat5e50m1mBED_50m2mBE2U-Aqeoiu31”

import os, glob

#searches for roots, directory and files
for root,dirs, files in os.walk(r"H:\My Documents\CrossTalk\\"):
   for f in files:
       if f == "Cat5e_1mBend1bottom50m2mBend2top":#string you want to rename
          try:
             os.rename('Cat5e_1mBend1bottom50m2mBend2top', 'Cat5e50m1mBED_50m2mBE2U'))
          except FileNotFoundError, e:
             print(str(e))

这是你想要的吗？

import os, glob
#searches for roots, directory and files
#Path
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
# rename arquivo1.txt to arquivo33.txt and arquivo2.txt to arquivo44.txt
renames={"arquivo1.txt":"arquivo33.txt","arquivo2.txt":"arquivo44.txt"}
for root,dirs,files in os.walk(p):
   for f in files:
      if f in renames.keys():#string you want to rename
         try:
            os.rename(os.path.join(root , f), os.path.join(root , renames[f]))
            print("Renaming ",f,"to",renames[f])
         except FileNotFoundError as e:
            print(str(e))

看看这是不是你想要的！！！

import os, glob
#searches for roots, directory and files
#Python 2.7
#Path 
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
#  if the substring in the key exists in the filename, replace the substring 
#   from the value of the key
#   if the key is "o1" and the value is "oPrinc1" and the filename is
#  arquivo1.txt ... The filename will be renamed to "arquivoPrinc1.txt"
renames={"o1":"oPrinc1","oldSubs":"newSubs"}
for root,dirs,files in os.walk(p):
    for f in files:
        for r in renames:
            if r in f:
                newFile = f.replace(r,renames[r],1)
                try:
                    os.rename(os.path.join(root , f), os.path.join(root , newFile))
                    print "Renaming ",f,"to",newFile
                except FileNotFoundError , e:
                    print str(e)