字符串的正则表达式

我想在Python中分割字符串。

示例字符串：

大家好，这是第一幕。场景 1 和场景 2，这是第二幕。场景 1 和 场景 2 及更多

进入以下列表：

['Hi this is', 'ACT I. SCENE 1', 'and', 'SCENE2', 'and this is', 'ACT II. SCENE 1',
 'and' , 'SCENE 2', 'and more']

有人可以帮我构建正则表达式吗？我构建的一个是：

(ACT [A-Z]+.\sSCENE\s[0-9]+)]?(.*)(SCENE [0-9]+)

但这不能正常工作。

如果我正确理解您的要求，您可以使用以下模式：

(?:ACT|SCENE).+?\d+|\S.*?(?=\s?(?:ACT|SCENE|$))

Demo https://regex101.com/r/XVkTkH/1.

分解：

(?:                    # Start of a non-capturing group.
    ACT|SCENE          # Matches either 'ACT' or 'SCENE'.
)                      # Close the non-capturing group.
.+?                    # Matches one or more characters (lazy matching).
\d+                    # Matches one or more digits.
|                      # Alternation (OR).
\S                     # Matches a non-whitespace character (to trim spaces).
.*?                    # Matches zero or more characters (lazy matching).
(?=                    # Start of a positive Lookahead (i.e., followed by...).
    \s?                # An optional whitespace character (to trim spaces).
    (?:ACT|SCENE|$)    # Followed by either 'ACT' or 'SCENE' or the end of the string.
)                      # Close the Lookahead.

Python 示例：

import re

regex = r"(?:ACT|SCENE).+?\d+|\S.*?(?=\s?(?:ACT|SCENE|$))"
test_str = "Hi this is ACT I. SCENE 1 and SCENE 2 and this is ACT II. SCENE 1 and SCENE 2 and more"

list = re.findall(regex, test_str)
print(list)

Output:

['Hi this is', 'ACT I. SCENE 1', 'and', 'SCENE 2', 'and this is', 'ACT II. SCENE 1', 'and', 'SCENE 2', 'and more']

在线尝试一下 https://rextester.com/LIAJC22538.